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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.

7 votes
Accepted

Exists $f \in I(X)$ such that $f(x) \neq 0$, $f(y) \neq 0$

Given an affine scheme $S=\operatorname {Spec (R)} $ and a closed subscheme $T=V(J)\subset S$, the restriction mapping $$\mathcal O(S)=R\to \mathcal O(T)=R/J$$ is obviously surjective. Applying this t …
Georges Elencwajg's user avatar
3 votes

determinant of normal bundle ample

Given an exact sequence of locally free sheaves $0\to E'\to E\to E''\to 0$ on, say, a ringed space, there is a canonical isomorphism $\text {det} E=\text {det} E'\otimes \text {det} E''$: this is pur …
Georges Elencwajg's user avatar
9 votes

Non-integral scheme having integral local rings

Hochster has an elegant construction which associates a commutative ring to each infinite totally ordered set with the property that strictly between two distinct elements there is a third one. The …
Georges Elencwajg's user avatar
14 votes

A GAGA question

Yes, it is true: the analytic and algebraic closures of $X$ in $Z$ coincide (and you don't need at all to assume that $Z$ is smooth). You may suppose that X is open in $Z$: if it isn't, just replace …
Georges Elencwajg's user avatar
4 votes

Nonsingular/Normal Schemes

Dear Randy, here is an easy to remember, terse slogan: Normal does not imply non-singular, except in dimension one, where it does. (Details in Hartshorne, Atiyah-MacDonald Prop.9.2 and all the other …
Georges Elencwajg's user avatar
7 votes

Component of Hilbert Scheme

The short (and unfriendly!) answer is that it is an irreducible component of the Hilbert scheme. Here is a slightly more detailed answer. Given a subvariety $X\subset \mathbb P^N$, you can attach to …
Georges Elencwajg's user avatar
8 votes

defining equations for secant varieties

There is an advanced monograph by F.L.ZAK on exactly this subject: "Tangents and secants of algebraic Varieties" (AMS, 1993, Translations of Mathematical Monographs 127). A free pdf version is online …
Georges Elencwajg's user avatar
5 votes

Algebraic data and purity associated to codimension greater than 2

The explanation why a lot of the algebraic data is encoded in lower dimension might reside partially in the following theorem. Let X/k be smooth and irreducible over the field k. Let $F \subset X $ b …
Georges Elencwajg's user avatar
21 votes

Union of closed subschemes with the structure sheaf over it

As with all definitions, there is no "proof" that the adopted definition is the right one but only a feeling that it better corresponds to our intuition. In the case at hand, taking $R/IJ$ as structu …
Georges Elencwajg's user avatar
8 votes

how to compute the dimension of secant variety

Dear mingming, you can find a lot of information on secant varieties in Harris's book "Algebraic Geometry, A First Course "(Springer GTM 133), essentially presented as a set of thoughtfully conceived …
Georges Elencwajg's user avatar
7 votes

Given a smooth algebraic curve in CP^n, why is the variety of trisecants at most two-dimensi...

Dear Undergraduate Student, first of all, congratulations on the beautiful geometry you chose to study so early in your studies. To prove $dim X_3 \leq 2$ it is indeed enough to prove that there exis …
Georges Elencwajg's user avatar
3 votes

What is the link between sections and sections? (schemes)

Dear Workitout, of course I can't prove there is no link, but I'm rather pessimistic . Here is a fuzzy argument in support of my feeling. The set of sections of $\mathcal O_X$ is never empty (after a …
Georges Elencwajg's user avatar
1 vote
Accepted

Jokes in Miles Reid's 'Undergraduate Algebraic Geometry'

Dear Robert, the joke on page 91 is that the ruled quadric depicted has "Central Electricity" written over it. It is an allusion to the cooling towers used by power plants. Here is the obligatory Wiki …
Georges Elencwajg's user avatar
5 votes
Accepted

Regular Morphism From Affine Line

Dear Damien, let's show that your morphism $f: \mathbb A^1_K \to \mathbb A^n_K $ is proper, hence closed, hence certainly has closed image. For that it is enough to prove that each $f_i:\mathbb A^1 …
Georges Elencwajg's user avatar
4 votes
Accepted

On Bourbaki's characterization of projectives...

Dear fishibones, an important point is that at the beginning of Chapter II, Bourbaki states that all the rings he will consider are commutative. This implies that if a free module has finite dimension …
Georges Elencwajg's user avatar

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