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Homotopy theory, homological algebra, algebraic treatments of manifolds.
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vote
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answer
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Singular cohomology as a Zariski sheaf
Let $X$ be a complex algebraic variety, and consider the presheaf
$U \mapsto H^i(U^{an}, \mathbb Z)$
in the Zariski topology. Is there a theorem that says this presheaf is already a sheaf, for certa …
9
votes
Fundamental groups of compact Kähler manifolds
As Donu mentioned, it is an open problem whether every Kähler group is projective, i.e. the fundamental group of a complex projective manifold (equivalently, a complex projective surface).
This questi …