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This tag is used if a reference is needed in a paper or textbook on a specific result.
3
votes
Anything about $\prod_{n \ge 1} (1 + n^{-n})$?
Logarithm $\log p$ of this product is also some definite integral (not a surprise, any number is a definite integral of appropriate function), but the integrand is more sophisticated than $x^{-x}$.
…
4
votes
Accepted
Maximum size of a union of incomparable chains
There is no such $c$. Assume that you have a set with $n$ elements, and maximal $B$ has $k$ elements. Take two copies $C$, $D$ of $A$ with disjoint supports. Add initial segment $1,1,\dots,1$ of lengt …
2
votes
Accepted
Lattice-point-free body diameter
For higher dimension, this does not hold, see the answer by Sergei Ivanov here.
For dimension 2, in the closed set $K$ without lattice-point free translate (in other words, such that $K$ has a point i …
4
votes
Sets with no "full" projection on sufficiently large subset of coordinates
Yes, as Christian Remling says, the maximal size of $S$ is indeed $\sum_{i<d} \binom{n}i$. This is known as the shattering lemma (found independently by Sauer, Shelah-Pearls, and Vapnik-Chervonenkis), …
3
votes
Accepted
Every connected planar graph contains adjacent vertices with at most 2 common neighbors
it is not what you are asking for (not a reference), but just maybe slightly easier proof, without searching for $K_{3,3}$. We may take any vertex $x$ of degree $d$, if any of $d$ vertices adjacent to …
3
votes
Maxwell's equations and differential forms
Bolibruch's nice explanation is here: http://www.mccme.ru/free-books/dubna/bol1.pdf
I do not know whether it has English translation, sorry.
10
votes
All polynomials are the sum of three others, each of which has only real roots
This is the answer only to my own question in the comments.
Two polynomials with real roots are not enough in general.
For seeing this, assume that $f(z)=\lambda g(z)+\mu h(z)$ for complex numbers $ …
7
votes
Inequality for the inner product in the probabilistic simplex
Let me explain how this may be solved without tricks, this may help for other similar issues.
1) The inequality must hold true for $\sum x_i\leqslant 1$, $\sum y_i\leqslant 1$ (instead of equalities …
6
votes
Is this a known question about the expression of a function on $\Bbb R^2$ as an infinite sum...
This is rather a comment to Nate Eldredge's answer, which reduces the (negative) answer to the existence of a set $\Omega\subset \mathbb{R}^2$ which is not a countable intersection of countable unions …
1
vote
Ear decompositions and spanning trees
This is not a reference, sorry.
The algorithm looks quite straightforward. We require additionally that for the vertex sets $V_0=V(C),V_i=V(C\cup P_1\ldots\cup P_i), i=1,2,\ldots$ the restriction $T( …
3
votes
Number of integer partitions modulo 3
Well, $f''f^2 +xf' ^3+2ff'^2 =0$ modulo 3 for $f=\prod(1-x^m)=\sum_{n\in \mathbb{Z} } (-1)^nx^{n(3n+1)/2}$ may be quickly seen as follows.
Differentiating the power series for $f$ and expanding the b …
8
votes
Primes of the form $4p+1$, with $p$ prime
I think what you ask about is a partial case of Bateman–Horn conjecture for polynomials $f_1(x)=x,f_2(x)=4x+1$. The expected value of $C$ equals $$(1-1/2)(1-1/2)^{-2}\prod_{p>2}\left\{(1-2/p)(1-1/p)^{ …
5
votes
An infinite version of the Dilworth theorem
There is an exercise in Stanley's Enumerative Combinatorics (Ex. 12 in Chapter 3 of Vol. 1): "True or false: if every chain and every antichain of a poset $P$ is finite, then $P$ is finite." It also c …
2
votes
Accepted
Linearly independent vectors from a family of subspaces
This is exactly Rado theorem on independent transversal (for the corresponding linear matroid).
Strictly speaking, to use it you should deal with finite sets, but a dimension of a vector subspace alwa …
10
votes
Accepted
Fraction of subsets with one-third sum
Denote these subsets which sum up to $s$ by $\alpha, \beta, \gamma$. Partition each subset $\alpha, \beta, \gamma$ onto two disjoint parts: $\alpha=\alpha_1\sqcup \alpha_2$,$\beta=\beta_1\sqcup \beta_ …