Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with laplace-transform
Search options not deleted
user 42259
2
votes
2
answers
575
views
How do I estimate/bound the error in an inverse Laplace transform?
Suppose I have a Laplace transform,
$$
F(s) = \int_0^{\infty}dx\ f(x)e^{-s x} \ .
$$
I know that
$$
F(s) \approx e^{A/(4s)}
$$
(for $s$ real) where $A$ is very large, and I want to estimate $f(x) …
- 21