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eigenvalues of matrices or operators

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eigenvalue of Laplacian matrix

And being symmetric it shares eigenvalues with its transpose. … $$ So the smallest eigenvalue of $B$ is given by $$\lambda(B)_0 =\arg \min_x x^T(A+A^T)x=\arg \min_x x^TAx+x^TA^Tx = 2\lambda(A)_0 \geq 0$$ It follows that $B$ is positive semidefinite since it's eigenvalues
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