Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 3996

Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.

3 votes

Dimension of polynomial algebras

This class of rings is studied by Arnold and Gilmer in the paper Jimmy T. Arnold and Robert Gilmer 'The Dimension Sequence of a Commutative Ring' American Journal of Mathematics , Vol. 96, No. 3 (19 …
J.C. Ottem's user avatar
  • 11.6k
9 votes

Nagata's bizzare examples

For 1), Nagata's counterexample goes as follows: Let $\mathbb{N}=A_1\cup A_2 \cup \cdots$ be a partition such that $|A_i|<|A_{i+1}|$. Take $S=k[x_1,x_2,\ldots]$, prime ideals $I_i=\langle x_i | i\in …
J.C. Ottem's user avatar
  • 11.6k
10 votes
Accepted

intersection of ideals in a commutative ring vs their product

I think this problem can in fact be handled by Gröbner basis theory in the case $A$ is a polynomial ring. Since $I\cdot J \subseteq I\cap J$ for any two ideals, one can simply compute a Gröbner basis …
J.C. Ottem's user avatar
  • 11.6k
17 votes

Non finitely-generated subalgebra of a finitely-generated algebra

It is easy to make examples of such subrings. For example, take $A=k[x,y]$ and consider the subring $$ B=k[x^a y^b : 0\le \frac{b}{a}<\sqrt{2}]. $$Geometrically, $B$ is spanned by monomials whose e …
8 votes
Accepted

Count the number of homogeneous polynomials

I guess what you are after is the Hilbert function of ideal. More precisely, if you have a multigraded polynomial ring $k[x_1,\ldots,x_n]$ and the ideal is given by $I=(f_1,\ldots,f_r)$, the Hilbert f …
J.C. Ottem's user avatar
  • 11.6k
6 votes
2 answers
2k views

When does the conormal bundle sequence split?

Let $X\subset \mathbb{P}^n$ be a smooth projective variety with ideal sheaf $I_X$. The conormal sequence is given by $$ 0\to I_X/I_X^2\to \Omega_{\mathbb{P}^n}|_X\to \Omega_{X}\to 0. $$ For which var …
J.C. Ottem's user avatar
  • 11.6k
15 votes

how to determine whether an ideal is prime or not by an algorithm

Let $R$ be a Noetherian ring and let $I$ be an ideal in $R[x]$. Then the following facts hold: $I$ is prime in $R[x]$ $\Longleftrightarrow$ $I\cap R$ is prime in $R$ and $\overline{I}$ is prime in $ …
J.C. Ottem's user avatar
  • 11.6k
16 votes

Geometric meaning of Cohen-Macaulay schemes

The geometric meaning of Corollary 18.17 in Eisenbud is that given an equidimensional scheme $X$ of dimension $n$ and a surjective morphism $\pi:X\to V$ where $V$ is a regular scheme of dimension $n …
J.C. Ottem's user avatar
  • 11.6k
5 votes

Minimal Free resolution of the ideals

The most basic motivation for studying resolutions is computing the Hilbert function/polynomial of $Y=V(I)$. The geometric information in this polynomial is essentially the dimension, the embedded deg …
J.C. Ottem's user avatar
  • 11.6k
6 votes

A question about an application of Molien's formula to find the generators and relations of ...

This follows from the Hilbert syzygy theorem. If $R=\mathbb{C}[x_0,\ldots,x_n]^G$ and $R^G$ is generated by elements $f_1,\ldots,f_r$ of degrees $a_1,\ldots,a_r$ respectively, $R^G$ has a free resolut …
J.C. Ottem's user avatar
  • 11.6k
11 votes
3 answers
2k views

When is a blow-up Cohen-Macaulay?

Let $X$ be a smooth projective variety and $Z$ a closed subscheme. Let $X'$ be the blow-up of $X$ with center $Z$. Under what conditions on $Z$ is $X'$ Cohen-Macaulay? In the case $Z$ is non- …
J.C. Ottem's user avatar
  • 11.6k