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(Co)chain complexes, abelian Categories, (pre)sheaves, (co)homology in various (possibly highly generalized) settings, spectra, derived functors, resolutions, spectral sequences, homotopy categories. Chain complexes in an abelian category form the heart of homological algebra.

2 votes
0 answers
108 views

When is a chain complex induced up to quasiisomorphism

I have a field extension $F/F'$ and an algebra $L'$ over $F'$. Let $L$ be the induced $F$-algebra $F\otimes_{F'}L'$ and $C_*$ a chain complex over $L$. Is there a good way to decide whether $C_*$ is …
HenrikRüping's user avatar
7 votes
Accepted

Question about spectral sequences associated to filtered complexes with unbounded filtrations

Suppose we have $\bigoplus_\mathbb{N}\mathbb{Z}$ and $\prod_\mathbb{N}\mathbb{Z}$. Both modules hava a canonical decreasing filtration where the $k$-th filtration step consists of all elements whose f …
HenrikRüping's user avatar
3 votes
2 answers
170 views

Equivariant maps of "higher order"

Given a group $G$, a ring $R$ and two $R[G]$-modules $M,N$. Then one can consider $Hom_R(M,N)$ and define inductively submodules $A_0,A_1,...$ via $A_0:=0$ $A_{n+1}:=\{ \;f\; |\; \forall\; g\in G: …
HenrikRüping's user avatar
4 votes

Functoriality of filtered spectral sequences

Let us use increasing filtrations $F^pC \subset F^{p+1}C\subset \ldots$. Then the homology of $C$ and $C'$ also inherit the structure of filtered modules by $F^pH(C) = im(H(F^p(C)\rightarrow C))$, or …
HenrikRüping's user avatar