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Homotopy theory, homological algebra, algebraic treatments of manifolds.
12
votes
4
answers
1k
views
Topologizing free abelian groups
For any set $S$ one can consider the free abelian group $\mathbb{Z}[S]$ generated by this set. Now suppose, there is a topology on $S$ given. Is it possible to find a topology on $\mathbb{Z}[S]$ in su …
12
votes
3
answers
526
views
Small simplicial set models for BG
Let $F$ be a finite group.
Is there a model for $BF$ as a simplicial set such that the number of nondegenerate $n$-simplices grows at most polynomially?
For example the Bar construction has the proper …
8
votes
Accepted
homotopy associative $H$-space and $coH$-space
I looked at my homotopy theory lecture notes and we had the following similar result:
$X$ H-CoGroup, $Y$ $H$-Group, then both group structures defined on [X,Y] agree.
The proof goes roughly as follows …
8
votes
0
answers
138
views
When is an ideal in the cohomology ring the kernel of a map induced by a map of spaces?
Let $X$ be a space and $I$ be an ideal in the cohomology ring $H^*(X)$.
I am interested in the question whether there is a map of spaces $Y\rightarrow X$ such that $I$ is the kernel of the induced map …
7
votes
Applications of homotopy groups of spheres
Wikipedia already gives a list of some examples.
7
votes
3
answers
454
views
Question concerning h-cobordisms
Suppose we have a cobordism $W$ of manifolds $M_0$ and $M_1$ and suppose the inclusion of $M_0$ into $W$ is a homotopy equivalence. Is the same true for the inclusion of $M_1$ (ie. is $W$ already an h …
7
votes
Accepted
Criteria for extending vector field on sphere to ball
View $B^{n}$ as $(S^{n-1}\times[0,1])/(S^{n-1}\times \{1\})$. This means that an extension of a map from $B^{n}$ to somewhere is just an extension to $S^{n-1}\times [0,1]$ which is constant on the oth …
6
votes
0
answers
398
views
Higher cohomology operations and spectral sequences
I was wondering how higher cohomology operations interact with spectral sequences.
For example if $X$ is a simplicial set. Then $C^*(X,\mathbb{F}_2)$ has an algebra structure over the Surjection Opera …
6
votes
Accepted
The fundamental group of an $S^1$-quotient
Suppose $S^1$ acts on $S^2$ by rotation around one axis. This action commutes with the antipodal map and hence gives an action on $\mathbb{R}P^2$. But $\mathbb{R}P^2/S^1\cong [0,1]$ and hence this can …
5
votes
Topological description of Manifold with boundary
For simplicity I want to stick to the compact, orientable case. Further i want to assume, that $N$ has the structure of a CW-complex.
It might still be interesting to consider the case, where the dim …
5
votes
Obstructions to $E_2$-algebra structure on $E_1$-algebra
Since I am most familiar with the (co)chain complex version (using the surjection operad (cf. McClure-Smith)), I will give an example in this setting. The surjection operad $S$ is also filtered by the …
5
votes
Adem relations of Steenrod square without modding out the coboundaries
I will make use of the surjection operad to produce an explicit example of a (functorial) cochain whose boundary is the Adem-Relation. Let us show that $Sq^1Sq^1([x])=0$ for a cohomology class $x$ in …
4
votes
0
answers
82
views
Number of surjections of a given complexity
Definition:
The complexity of a surjection $\{1,\ldots,n+k\}\rightarrow \{1,\ldots,n\}$ is defined in the following way. First think of this map as the tuple $(f(1),\ldots,f(n+k))$. For two numbers …
4
votes
Invariant neighborhood in a G-CW complex
I will call the property of a $G$-CW-complex that inside every neighborhood of a point one can find a $G$-invariant neighborhood property $A$.
As in your example, a graph where an edge stabilizer has …
4
votes
What is known about this cohomology operation?
Here are some examples. And since this really just adresses the computation part of the question and not what that map is, it is really just a partial answer.
LEt me first describe the sequence oper …