Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Enumerative combinatorics, graph theory, order theory, posets, matroids, designs and other discrete structures. It also includes algebraic, analytic and probabilistic combinatorics.
2
votes
Number of perfect matchings of the Dodecahedron
Here's a proof I concocted, utilising our favourite graph:
Consider the Petersen graph $P$, obtained from the dodecahedral graph $D$ by quotienting out by the antipodal map $\theta : D \rightarrow P$ …
11
votes
0
answers
181
views
Iterated automorphism groups of finite groups
Let $\mathcal{G}$ be the set of isomorphism classes of finite groups.
There is an operation $\mathrm{Aut} : \mathcal{G} \rightarrow \mathcal{G}$ which gives the automorphism group of a given group, u …
7
votes
When few simple conditions yield a unique intricate structure
The Leech lattice $\Lambda_{24}$ answers your question with quite a large multiplicity.
The unique $24$-dimensional laminated lattice, defined by $\Lambda_0$ being the one-point lattice and $\Lambda …
2
votes
How is the Penrose tiling decapod count of 62 calculated?
I get a total of $62$ by appealling to Burnside's lemma. In particular, note that the objects we are counting are 2-colourings of the vertices of a decagon up to:
Rotations;
Reflections composed wit …
26
votes
Puzzle on deleting k bits from binary vectors of length 3k
I can, at least, answer your question 'Is this in fact the correct answer?' with an affirmative 'no'.
Specifically, we can replace the upper bound $2^{n/3} \approxeq 1.26^n$ with the slightly better …
1
vote
1
answer
251
views
Natural bijection between sets with coloured elements?
In Andreas Blass's famous paper `Seven Trees in One', the existence of a natural bijection between binary trees and 7-tuples of binary trees is related to the equation $T^7 = T$ being satisfied by a c …
-1
votes
Self-complementary graph on 4k + 1 vertices
As the graph is self-complementary, by definition there exists some isomorphism $f$ from the graph to its complement. Consider $f$ as a bijection from the vertex-set of the graph to itself (i.e. a per …
1
vote
Maximum number of four cycles with no intersecting three vertex paths
EDIT: This answer pertains to a misinterpretation of the question before it was later clarified, so does not answer the question as currently stated:
Two distinct 4-cycles share a 3-vertex path if …
42
votes
1
answer
4k
views
Mathematicians wearing hats on arbitrary total orders
I've been pondering the following generalisation of a famous problem (the special case where $T = \mathbb{N})$:
Question: We have some totally-ordered set $T$ of mathematicians, each wearing a hat wh …
4
votes
Accepted
Product of geodesic distances
Note that if a graph is vertex-transitive, then it is `symmetric' by symmetry and we can wlog assume $i = 1$. The skeleton of the truncated icosidodecahedron is a counter-example to your conjecture, s …
7
votes
1
answer
144
views
Ramsey theory in infinite-dimensional projective spaces
Let $\mathbb{F}_q$ be a finite field and $k$ be a positive integer. If we colour each point of the infinite-dimensional projective space $\mathbb{F}_q \mathbb{P}^{\infty}$ with one of $k$ colours, can …
4
votes
Accepted
Ramsey theory in infinite-dimensional projective spaces
After further investigation, it appears that disappointingly the answer is 'no', and a proof appears in Lemma 2.4 of Partition Theorems for Subspaces of Vector Spaces (Cates and Hindman, 1975).
10
votes
Accepted
Finding the largest number which cannot be the sum of the labels of the Petersen graph
I can prove that all sufficiently large integers are representable.
Firstly, observe that there is a unique way, up to isomorphism, to choose three edges $p, q, r$ of the Petersen graph such that the …
2
votes
Geometric van der waerden theorem
Fedja has already answered one possible interpretation of your question in a comment, where the common ratio is required to be an integer. Here's further explanation, together with a multiplicative an …
5
votes
Accepted
Number of Hamiltonian cycles on 24-cell graph
The Held-Karp algorithm for TSP can be modified to count Hamiltonian cycles. The idea is to fix a starting vertex $v \in V$ and inductively count, for every vertex $w \neq v$ and subset $S \subseteq V …