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Linear representations of algebras and groups, Lie theory, associative algebras, multilinear algebra.
5
votes
2
answers
380
views
A general theory of multiplicity-free actions of $G\times H$?
There seem to be a bunch of different results of the form "This nice
representation $V$ of $G\times H$ breaks up as $\bigoplus_\lambda V_\lambda
\otimes W_\lambda$, where the $(V_\lambda)$ are distinc …
9
votes
1
answer
461
views
The highest root of an ADE quiver
Let $\Gamma$ be a finite subgroup of $SL_2({\mathbb C})$, and $Q$ the set of
its irreducible representations. McKay makes $Q$ into a directed graph by
having $V \to W$ if $W \leq V \otimes {\mathbb C} …
15
votes
2
answers
673
views
Relating two characterizations of ${\mathfrak sl}_{n > 2}$ among simple Lie algebras
Let $\mathfrak g$ be a finite-dimensional simple Lie algebra over $\mathbb C$.
Theorem 1. The highest root is perpendicular to all but one simple root, except in the case ${\mathfrak g}={\mathfrak sl …
6
votes
1
answer
241
views
Inner product on $V_{-\rho}$?
Prologue. To $M^n$ a compact real manifold with frame bundle $F$ (a principal $GL_n$ bundle), we associate a line bundle using the representation $M\mapsto \sqrt{|\det M|}$, the bundle of half-densiti …
5
votes
2
answers
307
views
Weight multiplicity formulae for $(\mathfrak g,B)$-irreps
Let $G$ be a complex reductive Lie group, $B$ a Borel subgroup, with which to define "dominant weight". Let $\lambda$ be an integral weight, not necessarily dominant, but nonetheless giving a one-dime …
9
votes
2
answers
371
views
Why do these two irreps of $E_6$ have the same dimension?
$E_6$'s Dynkin diagram is a line of 5 vertices, which we will number 1...5, and a sixth one attached to #3, which we will ignore.
$\dim V_{\omega_2} = 351 = \dim V_{2\ \omega_1}$, where $\omega_i$ den …
13
votes
0
answers
560
views
Are the extra vertices in Nakajima's doubling of a quiver related to Langlands duality?
To define a Nakajima quiver variety associated to a quiver $Q = (Q_0,Q_1)$
(vertices and arrows), one first doubles it to $Q^\heartsuit$ by attaching
an extra vertex to every old vertex in $Q_0$. Then …
10
votes
1
answer
348
views
Derivation of Blattner's conjecture in the Beilinson-Bernstein picture
On the last page of Schmid's article "Discrete Series", he says
"In the Beilinson-Bernstein picture, discrete series modules are attached to closed $K$-orbits in $X$... the $K_{\mathbb R}$-structure o …
42
votes
3
answers
3k
views
Are there "real" vs. "quaternionic" conjugacy classes in finite groups?
The complex irreps of a finite group come in three types: self-dual by a
symmetric form, self-dual by a symplectic form, and not self-dual at all.
In the first two cases, the character is real-valued, …
8
votes
1
answer
220
views
Cominuscule property of nilpotent orbits
Let $G$ be a complex reductive Lie group, $G/P$ a flag manifold,
and $\Phi: T^* G/P \to {\mathfrak g}^*$ the moment map. So $\Phi(T^* G/P)$ is the closure of a nilpotent orbit.
Lots of classes of ni …
6
votes
1
answer
565
views
Is there a "Cartan product" of Harish-Chandra modules?
If $\lambda,\mu$ are two dominant weights for a Lie group $G$, then
there is a canonical (up to scale, perhaps)
surjection $V_\lambda \otimes V_\mu \to V_{\lambda+\mu}$
of finite-dimensional represen …
16
votes
1
answer
665
views
Subquotients in the Verma filtration on Verma modules
Let $\lambda$ be a dominant integral weight of $\mathfrak g$, a finite-dimensional reductive Lie algebra over $\mathbb C$. Let $M(w\cdot \lambda)$ denote the Verma module with high weight $w\cdot \lam …
7
votes
0
answers
149
views
Eigenspaces and covering relations of twisted involutions
Let $\theta:G\to G$ be an involution of a complex connected reductive Lie group, preserving a maximal torus $T$ (which, for me, lies inside a $\theta$-invariant Borel $B$). Let $K = G^\theta$ be the f …
10
votes
0
answers
221
views
Branching from GL(a+b) to GL(a) x GL(b)$ using Gel'fand-Cetlin patterns
If one iterates the multiplicity-free branching rule from $\operatorname{GL}(n)$ representations (finite-dim, over $\mathbb C$) to $\operatorname{GL}(n-1)$ all the way down to $\operatorname{GL}(0)$, …
6
votes
2
answers
314
views
Covering relations in $K\backslash G/B$
Let $G$ be a simply connected complex Lie group, $\theta$ an involution,
and $K = G^\theta$ the fixed point subgroup. Pick a $\theta$-invariant
Borel subgroup $B$. Then there is a natural
map $K\backs …