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1 vote

Mutual information decrease with coarse-graining

For the case $\epsilon=0$, assume $A=X$ is uniform, and $B=Y$, and $C$ and $D$ are deterministically $0$. Then you say if $H(B) \le 0$ then $H(A\oplus B)\le 0$. But $H(A\oplus B) = H(A) = 1 \neq 0$, …
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