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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.
-1
votes
1
answer
152
views
$\ell^q$ analog of square function
It is a classical result in harmonic analysis that
$$ \|\|P_kf\|_{\ell^2_k}\|_{L^p_x}\approx\|f\|_{L^p} $$
for $p\in(1,\infty)$, where $P_k$ is the Littlewood-Paley decomposition onto frquency $\app …
2
votes
Accepted
Poincaré inequality on annular regions
No. Consider the positive part of a coordinate function on a large but thin annulus.
1
vote
Accepted
Characterization of a subset of the Sobolev space $H^k(0,2\pi)$ in terms of Fourier series
This is indeed true, and let me illustrate this in the special case $k=1$.
We are given a function $u\in H^1(0, 2\pi)$ such that $u(0)=u(2\pi)$. First we note that this boundary condition indeed make …
12
votes
2
answers
814
views
When is the closed unit ball in a smaller Banach space closed in a larger Banach space?
Recently I saw an interesting lemma:
For any $s>0$, the closed unit ball in $H^s$ is also closed in the $L^2$ norm. That is, suppose $u_j\in H^s$ and $\|u_j\|_{H^s}\le 1$. Suppose $u_j\to u$ in $L^2$ …
2
votes
1
answer
809
views
Decoupling in mixed norm spaces
Bourgain and Demeter's proof of the $L^2$ decoupling conjecture decouples $\|f\|_{L^p}$ into an $L^2$ sum of $\|f_\theta\|_{L^p}$, where $\hat f$ is supported on a curved hypersurface $S$, where $\the …
2
votes
0
answers
394
views
Hölder-Zygmund spaces of negative order
In the equation (1.1.17) in Proposition 1.1.6 (ii) in Alazard and Delort's Sobolev Estimates for Two Dimensional Water Waves, there appears a norm named $C^{-1}$, but in Chapter 6 (Appendix) of the sa …
4
votes
1
answer
288
views
Is there a name for this space?
I'm just asking if there is a name for the space of functions on $\mathbb R^n$ whose norm is defined by
$$ \|f\|=\|\hat f\|_{L^p} $$
for $p\in [1,\infty]$. I find it handy to give it a name when dis …
2
votes
Nash inequality on a compact domain?
Sometimes one has to roll up his sleeves and get his hands dirty in analysis.
So here is the estimate you need:
$$ \|f\|_2^2=(\sum_{|\xi|\le R}+\sum_{|\xi|>R}) |\hat f(\xi)|^2\ll_n R^n\sup_{\xi} |\h …
5
votes
Existence of a uniformly continuous function $g$ on $\mathbb{R}$ where $f = g$ a.e.?
This is easier when passed to some sort of weak formulation. By Lebesgue differentiation theorem, for almost every x, $\lim_{r\to0} \frac{1}{|B_r|} \int_{x+B_r} f=f(x)$. Replace each f(x) by the left …
4
votes
1
answer
353
views
Mixed norm estimate for the heat equation
Consider the inhomogeneous linear heat equation
$$\partial_tu-\Delta u=F$$
on $\mathbb R^n\times [0,1]$ (say) with zero initial data. Assume $F$ is very nice (say Schwarz), so that we have a nice so …
4
votes
Accepted
Fourier transform inversion theorem for a function not in L1 or L2
You can define the distributionial Fourier transform of a tempered distribution using all the abstract machinery established by Schwartz, and the thing you want to check is that it agrees with the int …
14
votes
Accepted
Can the topological algebra of analytic functions be endowed with a norm that defines the na...
For those who don't have the book (or have the wrong version), here is the proof that the topological vector space of holomorphic functions on the unit disk is not normable (i.e. whose topology is not …
9
votes
1
answer
903
views
The Fourier transform of a function supported on $B_1$ is essentially constant on $B_1$?
I'm going through the last steps of Bourgain and Demeter's proof of the $l^2$ decoupling conjecture, but I'm unable to see how the first inequality in (43) goes through. I'll water down the question a …
2
votes
Moser estimates?
Integrating by parts, using a cutoff function if necessary, we have
$$ \int_{B(r)} |\nabla u|^2\ll \int_{B(r)} a_{ij}\partial_iu\partial_ju=\int_{B(R)} uLu+O(u|\nabla u|)\ll \int_{B(R)} |u\nabla u|. …
1
vote
Infinitely many independent functions that are only frequency localized?
For all $a\in(0,K)$, the function $\hat 1_{[0,a]}$ is $K$-frequency localized, yet the function itself decays like $1/x$ as $x\to\infty$ (as easily seen by integration by parts), so it is not spatiall …