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Results tagged with riemann-zeta-function
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user 3659
The Riemann zeta function is the function of one complex variable $s$ defined by the series $\zeta(s) = \sum_{n \geq 1} \frac{1}{n^s}$ when $\operatorname{Re}(s)>1$. It admits a meromorphic continuation to $\mathbb{C}$ with only a simple pole at $1$. This function satisfies a functional equation relating the values at $s$ and $1-s$. This is the most simple example of an $L$-function and a central object of number theory.
12
votes
Sharpening of Lindelöf hypothesis
No. In fact it is known that for any $\varepsilon>0$ there are arbitrarily large values of $t$ with
$$ |\zeta(1/2+it)| \ge \exp\left( (1-\varepsilon) \sqrt{\frac{\log t}{\log \log t}} \ \right).$$
Thi …
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4
votes
On the critical line $ \Re \zeta'(s)/\zeta(s) =? 1/2 \log(\pi) - 1/2 \Re \psi(s/2)$ ?
Your formula follows from Hadamard's product formula for $\zeta(s)$ and the corresponding partial fraction decomposition of $\zeta'(s)/\zeta(s)$. See, for instance, section 2 of Soundararajan's paper: …
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6
votes
Accepted
Riemann Z function, bounds on number of non-trivial zeros along horizontal lines, rather tha...
It $t$ is not an ordinate of a zero of $\zeta(s)$, define
$$ S(t) = \frac{1}{\pi} \arg \zeta(1/2+it) = -\frac{1}{\pi} \Im \int_{1/2}^\infty \frac{\zeta'}{\zeta}(\sigma+it) d\sigma$$
and define
$$ S(t) …
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2
votes
Inequality for the modulus of Riemann zeta on horizontal lines and alleged partial result of...
GH has answered your question, but here is some additional remarks.
The function you are calling $F(s)$ is often called $\chi(s)$ in the theory of the Riemann zeta-function (e.g. in Titchmarsh's book …
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11
votes
Accepted
Axioms for Riemann $\zeta$ function
Perhaps you are looking for something like Hamburger's Theorem?
It states, essentially, that the only Dirichlet series with a finite number of singularities satisfying the same functional equation a …
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3
votes
Closed form for derivatives $\zeta^{(n)}(1/2)$
Edit: My original answer was incorrect.
You can evaluate $\zeta'(\frac{1}{2})$ recursively in terms of $\zeta(\frac{1}{2})$ using the symmetric form of the functional equation:
$$ \zeta(s)\Gamma(\tf …
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5
votes
Possible locations for non trivial zeroes lying off the critical line
Let $\chi(s)=2^s \pi^{s-1}\sin(\pi s/2) \Gamma(1-s)$ so that $\zeta(s)=\chi(s)\zeta(1-s)$. You are asking about the curve $|\chi(s)|=1$.
As you have observed, $|\chi(1/2+it)|=1$ for real $t$. There i …
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7
votes
Accepted
Is this sum of reciprocals of zeta zeros correct?
To answer your modified question, according to Mathematica:
$$ \lim_{s\to 0} \left(\frac{\hat{\zeta}'}{\hat{\zeta}}(s)+\frac{1}{s}\right) = -\frac{\gamma}{2} + \tfrac{1}{2}\log(4\pi).$$
This implies …
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14
votes
Accepted
Upper bounds on the difference of consecutive zeta zeros
Littlewood was the first to prove that the gaps between the ordinates of successive zeros of $\zeta(s)$ tend to zero. This is proved, for instance, in Titchmarsh's book on the zeta-function (see Theor …
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6
votes
Is this sum of reciprocals of zeta zeros correct?
Edit: I endorse Juan's answer to the original question. The sum $\displaystyle{\sum_{\rho} \tfrac{1}{|\rho|}}$, running over the non-trivial zeros $\rho$ of $\zeta(s)$, is known to diverge, so at best …
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38
votes
2
answers
2k
views
Optimization problem arising from the study of zeta zeros
Motivation: The following problem arose in [1] while studying the vertical distribution of the zeros of the Riemann zeta-function. At the time, my collaborators and I were unable to solve it and I hav …
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11
votes
Accepted
non-trivial zeros of partial zeta functions
The answer to question 1 is classical: Any Dirichlet series which has a finite abscissa of absolute convergence has a zero-free half-plane.
Suppose the Dirichlet series
$$ A(s)=\sum_{n=1}^\infty \fra …
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11
votes
Explicit formula for Riemann zeros counting function
Assuming the Riemann Hypothesis, you can use a smooth approximation to the characteristic function of an interval in the Guinand-Weil explicit formula to approximately count the number of zeros of the …
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11
votes
Accepted
Zeros of the derivative of Riemann's $\xi$-function
In exercise 1 on page 443 of their book "Multiplicative Number Theory," Montgomery & Vaughan outline a proof of the statement:
"Assuming the Riemann Hypothesis, $\xi'(s)=0 \implies \mathrm{Re}(s)=1 …
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