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Questions on group theory which concern finite groups.
7
votes
Accepted
How to prove that index of second smallest index subgroup in $A_n$ is $n \choose 2$?
Although some fiddling will be necessary to get a precise result, one can understand problems of this type without using powerful modern results in group theory.
For large enough $n$, there are a lot …
2
votes
quasiprimitive non-solvable groups
You might find useful the paper of Carlo Casolo, "Some linear actions of finite groups with $q^\prime$-orbits". If I understand correctly, this handles nonsolvable groups under the additional assumpt …
13
votes
Accepted
Groups with maximal element order 6
Let $P$ be a Sylow $3$-subgroup of $G$ (which we may assume to be nontrivial) and consider the conjugation action of $P$ on the set $X$ of all elements of order six in $G$. Remove from $X$ all of its …
4
votes
What groups have a second maximal subgroup below exactly four maximal subgroups?
I think that with some work you can characterize the examples where $G$ is solvable as follows. (I did not check carefully, so you can take this with a grain of salt.)
If $H$ has trivial core in $G$ …
5
votes
Accepted
The zero entries in the character table of a finite group
Here are infinitely many examples showing that the answer to question 1 is negative. Take $n \equiv 1 \bmod 4$ with $n>5$ and let $\chi$ be the character of the symmetric group $S_n$ associated to th …
3
votes
Generating symmetric groups with small cycles
Let $p$ be the smallest prime divisor of $n$. I believe that $f(n)=n/p+1$. The key points are as follows.
1) If $H \leq S_n$ is primitive and contains a $2$-cycle, then $H=S_n$.
2) If $1<k \leq m< …
4
votes
Accepted
Existence (or the number) of generating triple of involutions of $\operatorname{PGL}_2(p)$ w...
Such triples exist, I think.
First, embed $PGL_2(p)$ in $S_{p+1}$ through its action on $1$-spaces from ${\mathbf F}_p^2$. This maps elements of order $p+1$ in $PGL_2(p)$ to $(p+1)$-cycles, and el …
13
votes
Accepted
Transitive subgroup of $S_p$ containing a $p$-cycle and a double transposition
I believe that it was already known to Jordan that if $n \geq 8$ and $G$ is a primitive subgroup of $S_n$ containing a double transposition, then $G$ contains $A_n$. As a subgroup of $S_p$ containing …
1
vote
Are the orders of the generators of a group and the product of pairs of thereof enough for t...
Maybe I misunderstand the question. I interpret it as follows: you have a finite group $G$ and some (minimal) set $S$ of generators for $G$ that satisfies the relations defining a Coxeter group $W$ w …
12
votes
Accepted
Primitive, non-2-transitive groups with very large orbitals?
Let $G=S_n$, acting on the ${{n} \choose {2}}$ $2$-sets from $[n]$. The stabilizer of a $2$-set $X$ is maximal in $S_n$ and has two orbits on the remaining $2$-sets, one consisting of those that inte …
6
votes
Accepted
Combinatorial problem in $\mathsf{S}_4$
Please allow me to substitute as follows in order to avoid typos: $r_{11}=a$, $r_{12}=b$, $r_{21}=c$, $r_{22}=d$, $t_{21}=e$, $t_{22}=f$.
Upon examining the character tables of $S_4$, $A_4$, and $D_8$ …
2
votes
Accepted
Combinatorial problem in $G(32, \, 6)$
Here is a proof by contradiction. Assume an $8$-tuple $E$ from $G$ satisfies all of your relations.
Let $\Phi=\langle w^2,x,y \rangle \leq G$. It is straightforward to observe that
(A) $\Phi$ is abel …
2
votes
Accepted
What are the rank 3 boolean intervals [H,G], with G simple group?
Here is another infinite class of examples: Say $q>3$ is a prime power and $a$ is a square-free odd integer. Then $L_2(q)$ embeds in $L_2(q^a)$, and the lattice of subgroups above the image of such a …
3
votes
What are some interesting corollaries of the classification of finite simple groups?
Maybe it is difficult to say what is strictly "outside" of finite group theory. However, to add to Igor's answers, I can suggest that you look at the work of Bob Guralnick and various collaborators. …
5
votes
Accepted
Generalization of the fundamental theorem of cyclic groups
Say $G=S_n$ and $H$ is a Young subgroup with three orbits, no two of which have the same size and no two of which have sizes summing to $n/2$. Then the only subgroups between $H$ and $G$ should be th …