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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.
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Is BV2 space closed in L2 space?
We define the BV2 space by
$S = \lbrace f\in L^2:\textrm{TV}(f)<\infty\rbrace$, where $TV(f)=\sup_{g\in C_c^1,\|g\|_\infty\leq 1}\int f\cdot \textrm{div}g$.
My question is: is $S$ closed in $L^2$?
T …