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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

8 votes
Accepted

any ellipse with rational axes and circumference?

No, there is no such ellipse. This is exactly theorem $6.5$ of Alan Baker's book TRANSCENDENTAL NUMBER THEORY, as pointed out by Felipe Voloch. Let $\omega$ be a primitive period of a $\wp$-function …
Dietrich Burde's user avatar
6 votes

Argument of a Gauss sum

Here is a remark, if $\chi$ is a quadratic character. Then there is a remarkable result of Gauss, saying that $$ G(\chi, N)=\begin{cases} \sqrt{N}, \;\text{ if } N\equiv 1 (4) \cr 0, \; \text{ if } N …
Dietrich Burde's user avatar
1 vote

Roth's theorem and exponential diophantine equations

The main application of the (generalized) Thue-Siegel-Roth theorem to exponential Diophantine equations comes from Schmidt's subspace theorem, and an extension to $p$-adic valuations due to H.P. Schli …
Dietrich Burde's user avatar
4 votes
Accepted

The maximum difference between the nth prime number and n x ln(n)

There are several good inequalities for this difference, e.g., $$ n \log n + n(\log \log n -1)<P(n) < n \log n + n\log \log n $$ for all $n\ge 6$, which can be derived from the prime number theorem. B …
Dietrich Burde's user avatar
5 votes
Accepted

Reference request: a class of diophantine equations

I just want to make a comment, that one can in general find a lot of information on the (primitive) integer solutions of the generalized Fermat equation $Ax^p+By^q=Cz^r$ (depending on the three cases …
Dietrich Burde's user avatar
3 votes

On a conjecture related to the classification of finite simple groups

Yes, counterexamples are easy to construct. Take $p=3$ and $n=7$. Then $3^7-1=2186=2\cdot 1093$ with the prime $1093$. Hence $\phi(3^7-1)=\phi(1093)=1092=2\cdot 3\cdot 7\cdot 13$ is divisible by $3$. …
Dietrich Burde's user avatar
2 votes

Can the Repdigit 77...77 be the sum of two squares?

This is not an answer, but just an observation, which Martin had probably in mind. By Fermat we know that $n=x^2+y^2$ is the sum of two squares iff the primes $p$ dividing $n$ with $p\equiv 3$ mod $4 …
Dietrich Burde's user avatar
3 votes
Accepted

Generalized Lehmer Euler Conjecture

I am not an expert here, but I think it has been implicitly considered in the context of $k$-Lehmer numbers. These are the positive composite integers $n\ge 1$ which satisfy $\phi(n)\mid (n-1)^k$, whe …
Dietrich Burde's user avatar
1 vote

Trying to solve: Show that n does not divide 3^n - 2^n for n greater than or equal to 2.

EDIT: I correct my answer. We have $3^n -2^n\equiv 1 \mod p$ for the smallest prime divisor $p$ of $n$. The proof is the same as the one by Gjergji Zaimi. Write $n=p^k\ell$ and use Fermat's little th …
Dietrich Burde's user avatar
5 votes

Why to count integers that are relatively prime to their euler function?

If $G$ is a group of order $n$ with $gcd(n,\phi(n))=1$, then $G$ is cyclic. Conversely, if $n$ is an integer, such that every group of order $n$ is cyclic, then $gcd(n,\phi(n))=1$. So, counting these …
Dietrich Burde's user avatar
5 votes
Accepted

Least quadratic residue and nonresidue

There is the following result of Wolke from $1967$ (which is perhaps not the best, but quite good). Theorem: Let $p$ be an odd prime, and $L(s,\chi)$ the $L$-series for the Dirichlet character $(n/p)$ …
Dietrich Burde's user avatar
5 votes

Diophantine equations with egyptian fractions

There is a nice survey article, Paul Erdös and Egyptian Fractions by R.L. Graham, also referring to the well-known Erdős–Straus conjecture.
Dietrich Burde's user avatar
7 votes
Accepted

A Sequence of Real numbers

It is well known that $\sum_{k\le x} \phi(k)=\frac{3}{\pi^2}x^2+O(x\log(x))$. In a similar way we obtain $$ \sum_{k\le x} \frac{\phi(k)}{k}=\frac{6}{\pi^2}x+O(\log(x)), $$ by using the Moebius functio …
Dietrich Burde's user avatar
1 vote

GCD computation for multiple polynomials and degree of Bezout coefficients

You can just recursively compute the gcd of $t\ge 2$ polynomials by $$ \gcd(P_1, P_2, \dots , P_t) = \gcd( P_1, \gcd(P_2, \dots , P_t)), $$ starting with $\gcd(P_{t-1},P_t)$, $\gcd(P_{t-2}, \gcd(P_{t- …
Dietrich Burde's user avatar
8 votes
Accepted

Diophantine equation - $a^4+b^4=c^4+d^4$ ($a,b,c,d > 0$)

Euler wrote $a^4-d^4=c^4-b^4$ with $a=p+q, d=p−q, c=r+s$ and $b=r−s$, obtaining $pq(pp + qq) = rs(rr + ss)$, and then did several other special transformations, until he arrived at the special solutio …
Dietrich Burde's user avatar

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