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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
8
votes
Accepted
any ellipse with rational axes and circumference?
No, there is no such ellipse. This is exactly theorem $6.5$ of Alan Baker's book TRANSCENDENTAL
NUMBER THEORY, as pointed out by Felipe Voloch.
Let $\omega$ be a primitive period of a $\wp$-function …
6
votes
Argument of a Gauss sum
Here is a remark, if $\chi$ is a quadratic character. Then there is a remarkable result of Gauss, saying that
$$
G(\chi, N)=\begin{cases} \sqrt{N}, \;\text{ if } N\equiv 1 (4) \cr 0, \; \text{ if } N …
1
vote
Roth's theorem and exponential diophantine equations
The main application of the (generalized) Thue-Siegel-Roth theorem to exponential Diophantine equations comes from Schmidt's subspace theorem, and an extension to $p$-adic valuations due to H.P. Schli …
4
votes
Accepted
The maximum difference between the nth prime number and n x ln(n)
There are several good inequalities for this difference, e.g.,
$$
n \log n + n(\log \log n -1)<P(n) < n \log n + n\log \log n
$$
for all $n\ge 6$, which can be derived from the prime number theorem.
B …
5
votes
Accepted
Reference request: a class of diophantine equations
I just want to make a comment, that one can in general find a lot of information on the (primitive) integer solutions of the generalized Fermat equation $Ax^p+By^q=Cz^r$ (depending on the three cases …
3
votes
On a conjecture related to the classification of finite simple groups
Yes, counterexamples are easy to construct. Take $p=3$ and $n=7$. Then $3^7-1=2186=2\cdot 1093$ with the prime $1093$. Hence $\phi(3^7-1)=\phi(1093)=1092=2\cdot 3\cdot 7\cdot 13$ is divisible by $3$. …
2
votes
Can the Repdigit 77...77 be the sum of two squares?
This is not an answer, but just an observation, which Martin had probably in mind. By Fermat we know that $n=x^2+y^2$ is the sum of two squares iff the primes $p$ dividing $n$ with $p\equiv 3$ mod $4 …
3
votes
Accepted
Generalized Lehmer Euler Conjecture
I am not an expert here, but I think it has been implicitly considered in the context of $k$-Lehmer numbers.
These are the positive composite integers $n\ge 1$ which satisfy $\phi(n)\mid (n-1)^k$, whe …
1
vote
Trying to solve: Show that n does not divide 3^n - 2^n for n greater than or equal to 2.
EDIT: I correct my answer. We have $3^n -2^n\equiv 1 \mod p$ for the smallest prime divisor $p$ of $n$.
The proof is the same as the one by Gjergji Zaimi. Write $n=p^k\ell$ and use Fermat's little th …
5
votes
Why to count integers that are relatively prime to their euler function?
If $G$ is a group of order $n$ with $gcd(n,\phi(n))=1$, then $G$ is cyclic. Conversely, if
$n$ is an integer, such that every group of order $n$ is cyclic, then $gcd(n,\phi(n))=1$.
So, counting these …
5
votes
Accepted
Least quadratic residue and nonresidue
There is the following result of Wolke from $1967$ (which is perhaps not the best, but quite good).
Theorem: Let $p$ be an odd prime, and $L(s,\chi)$ the $L$-series for the Dirichlet
character $(n/p)$ …
5
votes
Diophantine equations with egyptian fractions
There is a nice survey article, Paul Erdös and Egyptian Fractions by R.L. Graham, also referring to the well-known Erdős–Straus conjecture.
7
votes
Accepted
A Sequence of Real numbers
It is well known that $\sum_{k\le x} \phi(k)=\frac{3}{\pi^2}x^2+O(x\log(x))$. In a similar way we obtain
$$
\sum_{k\le x} \frac{\phi(k)}{k}=\frac{6}{\pi^2}x+O(\log(x)),
$$
by using the Moebius functio …
1
vote
GCD computation for multiple polynomials and degree of Bezout coefficients
You can just recursively compute the gcd of $t\ge 2$ polynomials by
$$
\gcd(P_1, P_2, \dots , P_t) = \gcd( P_1, \gcd(P_2, \dots , P_t)),
$$
starting with $\gcd(P_{t-1},P_t)$, $\gcd(P_{t-2}, \gcd(P_{t- …
8
votes
Accepted
Diophantine equation - $a^4+b^4=c^4+d^4$ ($a,b,c,d > 0$)
Euler wrote $a^4-d^4=c^4-b^4$ with $a=p+q, d=p−q, c=r+s$ and $b=r−s$, obtaining
$pq(pp + qq) = rs(rr + ss)$, and then did several other special transformations, until
he arrived at the special solutio …