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Questions about the branch of algebra that deals with groups.

2 votes

Generating sets for $\mathrm{SU}(1,1;\mathcal{O}_K)$ or $\mathrm{PU}(1,1;\mathcal{O}_K)$?

To expand on my comment above : as noted by john mangual $SU(1,1)$ is isomorphic to $SL(2, \mathbb R)$. If $h$ is an Hermitian form defined over a ring of integers $\mathcal O_K$, where $K$ is imagina …
Jean Raimbault's user avatar
2 votes
1 answer
182 views

Fixed directions and Zariski density of hyperbolic groups

It is a fact that if $\Lambda$ is a nonelementary subgroup of ${\rm PSL_2}(\mathbb{C})$ which contains an hyperbolic transformation and moreover ${\rm tr}(g)\in\mathbb{R}/\pm 1$ for all $g\in\Lambda$ …
Jean Raimbault's user avatar
8 votes
Accepted

Morphisms $\mathrm{SL}_n(\mathbb Z) \to \mathrm{SL}_m(\mathbb Z)$

I'll try to flesh out the first comment to give an answer: for all $n\ge 4$ there is a representation $\rho:A_{n+1}\to \rm SL_n(\bf Z)$ whose image normally generates $\rm SL_n(\bf Z)$ (because it inj …
Jean Raimbault's user avatar
1 vote

Generators for a certain congruence subgroup of SL(n,Z)

I guess the folllowing is a short explicit proof of Tits' result for this very special case, assuming CSP for $\rm{SL}_n(\bf{Z})$ (so this should be seen as a lenghty comment on the above answer). Th …
Jean Raimbault's user avatar
7 votes
Accepted

Unique product group which is not right orderable

Such a group has been found by N. Dunfield, see the appendix to the paper Steffen Kionke, Jean Raimbault, Nathan Dunfield, On geometric aspects of diffuse groups, Documenta Mathematica, Vol. 21 (2016 …
Jean Raimbault's user avatar
8 votes
0 answers
340 views

Polynomial growth without Gromov's theorem

It is a consequence of the theorem of M. Gromov on groups with polynomial growth and a result of P. Pansu(*) that if a finitely generated group $\Gamma = \langle S\rangle,\, S=S^{-1}$ satisfies $(\dag …
Jean Raimbault's user avatar
23 votes
1 answer
1k views

Kaplansky's unit conjecture and unique products

There are three conjectures on group rings that bear the name of Kaplansky (see for example this question). The 'unit conjecture' in the title of the present question is the strongest of them, and sta …
Jean Raimbault's user avatar
7 votes
2 answers
912 views

Subgroups of $SL_2(F)$ generated by unipotent elements

I am interested in the following problem : given a finite field $F$ and two unipotent elements $g_1,g_2\in\mathrm{SL}_2(F)$ which do not commute, what can we say about the subgroup they generate? More …
Jean Raimbault's user avatar
14 votes
1 answer
932 views

The number of involutions in a permutation group

If $G$ is a group let $I(G)$ be the number of involutions (elements of order 2) in $G$. My question is then easily stated: does there exists a constant $C > 1$ such that for every $n \ge 1$ and every …
Jean Raimbault's user avatar
7 votes
1 answer
435 views

A criterion for loxodromicity in Gromov-hyperbolic spaces

Recall that an isometry of a Gromov-hyperbolic space $X$ is called loxodromic if it has exactly two fixed points on the Gromov boundary $\partial X$, one being "attracting" and the other "repelling". …
Jean Raimbault's user avatar
1 vote

About normalizers of infinite cyclic subgroups of Hilbert modular group

This is not a complete answer but it's too long to fit in a comment, so here it goes. In case $g \in \mathrm{SL}_2(\mathcal O_k)$ is semisimple there are two possibilities : As you observed, if $g$ …
Jean Raimbault's user avatar
9 votes
Accepted

Equivalence of surjections from a surface group to a free group

This is true, and it is written up in lemma 2.2 of "The co-rank conjecture for 3--manifold groups" by C. Leininger and A. Reid https://arxiv.org/abs/math/0202261. They state the result in slightly dif …
Jean Raimbault's user avatar
10 votes
Accepted

Random pairs of commuting permutations

This is not the case, in fact in both cases the limit is 1/2. This is because with probability going to 1 as $n \to +\infty$ a uniformly random morphism $\mathbb F_2 \times \mathbb F_2 \to \mathrm{Sym …
Jean Raimbault's user avatar
3 votes

A question about congruence subgroups

This is true in general, by an argument similar to the one you used for the coprime case. The subgroup $\Gamma$ generated by $\Gamma(N_1) \cup \Gamma(N_2)$ contains the matrices $$ a = \begin{pmatrix …
Jean Raimbault's user avatar
4 votes
1 answer
248 views

Subgroups and representations of finite groups of Lie type

Is there a usable bound for the minimal index of a proper subgroup in a finite simple group of Lie type in terms of its rank and the characteristic (or even cardinality) of its field of definition? On …
Jean Raimbault's user avatar

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