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6
votes
Is the hierarchy of relative geometric constructibility by straightedge and compass a dense ...
I've figured out how to do the finite graph case, in the negative. The ordering of quadratically closed fields is not dense in that case either. Throughout let $qcl(F)$ denote the quadratic closure …
19
votes
Accepted
Is the hierarchy of relative geometric constructibility by straightedge and compass a dense ...
There are three answers. Throughout let $qcl(F)$ be the quadratic closure of a field $F$ inside $\mathbb{C}$.
Part 1: Yes there is a quadratically closed field strictly between $qcl(\mathbb{Q})$ and …