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Dynamics of holomorphic transformations; Mandelbrot and Julia sets.
22
votes
Accepted
Poincaré metric on the Riemann sphere minus more than two points
Yes. The density of the Poincare metric with respect to the spherical metric is
a positive continuous function which tends to infinity at the punctures. Thus it
is bounded from below by some positive …
18
votes
Accepted
Can the topologist's sine curve be realized as a Julia set?
The answer is negative. Since every neighborhood of a point
on the Julia set is mapped onto the whole Julia set by some iterate of the rational function, it follows that if a small piece of the Julia …
17
votes
Accepted
On entire functions with polynomial Schwarzian derivative
The answer is this:
$$f(z)=\int_{z_0}^z e^{Q(\zeta)}d\zeta,$$
where $Q$ is a polynomial, and this is the general form of
an entire function whose Schwarzian is a polynomial. The crucial fact that $f$ …
16
votes
The deep significance of the question of the Mandelbrot set's local connectedness?
MLC is indeed a very technical and complicated counterpart of a simple question which arises from
the general theory of dynamical systems.
For a generic system (in a given finitely-parametric family) …
14
votes
On complex dynamics in high dimensions
Main areas are dynamics of automorphisms (for example, Henon maps), dynamics of endomorphisms, dynamics of foliations, and local dynamics.
Eric Bedford, Tien-Cuong Dinh, John Fornaess, Misha Lyubich, …
13
votes
How is the Julia set of $fg$ related to the Julia set of $gf$?
Answer. $J(fg)$ is the full $g$-preimage of $J(gf)$. (And vice versa with interchange of
$f$ and $g$).
Proof. Let $A=fg$ and $B=gf$. Then we have a semi-conjugacy $gA=Bg$.
Now it is a general fact, …
11
votes
If I have zeros at the vertices of an icosahedron, where should the poles go?
MR1032073
Doyle, Peter; McMullen, Curt,
Solving the quintic by iteration.
Acta Math. 163 (1989), no. 3-4, 151–180.
10
votes
Who proved that the Mandelbrot set's Julia sets are locally connected?
Nobody. This is the principal unsolved problem in the area, which is called MLC
(That the Mandelbrot set is locally connected). Two Fields medals were awarded for
partial progress in this problem.
Ab …
10
votes
Accepted
Does the Mandelbrot set have dense interior?
The answer is positive and this is not difficult (a normal families argument). The boundary
of the Mandelbrot set is the set of $J$-instability. Every point $c_0$ of this set is a limit of $c_n$ such …
8
votes
Periodicity in iterated powers of sin, cos, exp
You iterate the function $a\mapsto (\cos a)^z$ which is ill defined for complex $a$ and $z$; you need a branch cut, which is visible on some of your pictures.
In holomorphic dynamics, usually entire f …
8
votes
Accepted
Ahlfors' proof of Bloch's theorem
He explains his choice in lines 8-9 on p. 364 of the paper:
"This metric has the curvature $-4$ for it is obtained from the hyperbolic metric by the transformation $w'=w^{1/2}$ ."
Remarks. By more sop …
7
votes
Convergence of Newton's method
Your statement that iterates of the Newton method converge to a cycle almost everywhere is equivalent to the statement that for every polynomial $f$
the Julia set of the rational function $z-f(z)/f'(z …
7
votes
Accepted
Smooth Julia set for quadratic polynomials
The answer to a) is yes, and this was proved by Fatou in 1919.
Sur les équations fonctionnelles
Bulletin de la S. M. F., tome 48 (1920), p. 208-314.
There are many generalizations of this fact. For o …
7
votes
Accepted
Power series expansion of the Koenigs function
You do not tell the crucial thing: how large is $|f'(0)|$.
There is no simple expression for coefficients or any other simple expression for $h$,
even when $f$ is quadratic polynomial $\lambda z+z^2$. …
6
votes
Is there an (almost) dense set of quadratic polynomials which is not in the interior of the ...
Yes, these are the neighborhoods of certain Misiuriewicz points,
see for example the right picture in the bottom here:
http://classes.yale.edu/fractals/MandelSet/MandelBoundary/Mis.html