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Results tagged with lyndon-words
Search options answers only
not deleted
user 25256
5
votes
Accepted
Bracket of lyndon words?
Yes it is of this form because any Lie polynomial
"begins" by a Lyndon word, in particular, the least
monomial of $B(l)$ is $l$. Then
$$
B(m)=m+\sum_{m<u\atop |u|=|m|} \alpha^{(u)}u;\ B(n)=n+\sum_{ …
- 3,738