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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

9 votes

Towards the complex unit conjecture

There are no such obstacles a posteriori since the complex unit conjecture is false.
Giles Gardam's user avatar
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2 votes

Group ring and left zero divisor

If $G$ is torsion-free then the question of reversibility of $K[G]$ (that is, does $ab = 0$ imply $ba = 0$) is in fact equivalent to the zero divisor conjecture, for any field $K$. Connell showed that …
Giles Gardam's user avatar
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1 vote

Zero divisor conjecture for finite fields

For a fixed group $G$, the zero divisor conjecture over $\mathbb{C}$ is implied by the zero divisor conjecture over an algebraically closed field of positive characteristic, so in particular it would …
Giles Gardam's user avatar
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6 votes
Accepted

Examples of Noetherian integral group ring

There are no known examples of groups with Noetherian integral group rings other than virtually polycyclic groups. The following result and subsequent text is quoted from Kropholler, Peter; Lorensen, …
Giles Gardam's user avatar
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8 votes

What is the current status of the Kaplansky zero-divisor conjecture for group rings?

Since there's been a request for an update on the zero divisor conjecture, let me give one. The zero divisor conjecture is open. I'll update this answer if I hear otherwise. Alain already mentioned th …
Giles Gardam's user avatar
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50 votes

What is the current status of the Kaplansky zero-divisor conjecture for group rings?

Apologies for the self-promotion, but there is now a counterexample to the unit conjecture (U) with $K=\mathbb{F}_2$ and virtually abelian $G = \langle a, b \,|\, (a^2)^b=a^{-2}, (b^2)^a=b^{-2} \rangl …
Giles Gardam's user avatar
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