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2
votes
Accepted
Intuition behind $\lambda$-pure subobjects
Think of the category of structures in some signature $\Sigma$. The functor represented by a finitely presentable object $F$, say, corresponds to some term in the language generated by $\Sigma$. For e …
4
votes
In a locally presentable category, is every object (a retract of) the colimit of a chain of ...
Since this result is derived by Lieberman, Rosicky, and Vasey as a corollary of some more sophisticated constructions with more sophisticated goals, I think it might be worth "compiling out" the proof …
3
votes
Example: Accessible category without colimits
Here's a general way to get an accessible category that likely will not have many colimits: let $C$ be a locally presentable category, and then let $C^{mono}$ be the category with the same objects as …
9
votes
Accepted
What are the reflective subcategories of the category of presentable categories?
Some ideas, building off of Simon Henry and Ivan di Liberti's remarks:
$Pr^L$ is in fact essentially a large (not huge) category (in either the ordinary or $\infty$ context).
That is, let $\lambda$ …
2
votes
Accepted
If $\mathcal C$ is a $\kappa$-accessible $\infty$-category, then is $Mor \mathcal C$ $\kappa...
Marc Hoyois answered in the comments: the answer is affirmative, by HTT 5.3.5.15.
2
votes
When is the homotopy category of an accessible $\infty$-category accessible?
Here's a further generalization:
Claim: Let $\mathcal T$ be a triangulated category and with a $t$-structure such that $\mathcal T^\heartsuit$ is has coproducts, which are exact. Suppose there exi …
2
votes
When is the homotopy category of an accessible $\infty$-category accessible?
Here's something we can say which addresses a large class of examples. Let us say that a (possibly noncommutative) ring $R$ is not zero-dimensional if there exists $r \in R$ which is neither a right u …
4
votes
Accepted
Is every limit-closed, accessibly-embedded full subcategory of a presentable $\infty$-catego...
A few years later, this is proven, by Ragimov and Schlank.