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Questions about Kähler manifolds and Kähler metrics.
4
votes
Extension of strictly plurisubharmonic functions on a Kähler manifold
No, in general.
A trivial reason is that $f$ may not extend to a smooth function in a neighbourhood of $\overline{M\setminus A}$, but you can easily get around that by asking that $f$ agree with $h$ …
5
votes
Accepted
Clifford Action for Kahler Manifolds
You ask for a short-cut, and I'm going to interpret this as asking "How can I see that on a Kaehler manifold $X$ the forms $\Omega^{0,\bullet}_X$ are a complex Clifford module, without first going thr …
43
votes
Accepted
Kähler structure on cotangent bundle?
This is true! I assume $M$ compact.
Method 1. Real algebraic geometry. Cf. Fukaya, Seidel, and Smith - Exact Lagrangian submanifolds in simply-connected cotangent bundles. By a version of the Nash–To …