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for questions involving inequalities, upper and lower bounds.
4
votes
1
answer
232
views
Optimal constant in Carleman's inequality
Let $(a_j)_{j\ge 1}$ be a sequence of positive real numbers. Carleman's inequality says that
$$
\sum_{n\ge 1}\left(\prod_{1\le j\le n} a_j\right)^{1/n}< e\sum_{n\ge 1} a_n.
$$
The constant $e$ is opti …
2
votes
1
answer
200
views
Sobolev spaces based on $L^p$ with $0<p<1$
I am looking for references on the topic of Sobolev spaces based on $L^p$ with $0<p<1$.
For instance, a natural question could be: let $u$ be a (compactly supported) distribution on $\mathbb R^n$ suc …
2
votes
Is the 2D Ladyzhenskaya inequality true for periodic functions?
Let us start with the so-called Gagliardo-Nirenberg Inequality in $n$ dimensions,
$$
\Vert u\Vert_{L^{n/(n-1)}(\mathbb R^n)}\le c_n\Vert \nabla u\Vert_{L^{1}(\mathbb R^n)},
\tag{GN}$$
an inequality th …
1
vote
Local fractional Sobolev inequality
For $\epsilon >0$, $u\in H^{\frac{n}{2}+2\epsilon}$, $N_0=-\Delta+1$,
$$
\Vert N_0^{\frac{n}{4}+\epsilon} u\Vert_{L^2}=\Vert u\Vert_{H^{\frac{n}{2}+2\epsilon}}\ge c_{n,\epsilon}
\Vert u\Vert_{L^\inf …
2
votes
Accepted
An inequality involving multi-index
The first inequality with constant 1 follows from
$
\vert x^\alpha\vert\le\Vert x\Vert_{\infty}^{\vert \alpha \vert},\quad\text{where $\Vert x\Vert_{\infty}$ is the sup-norm.}
$
The second equality, …
0
votes
Show that $(\sum_{k=1}^{n}x_{k}\cos{k})^2+(\sum_{k=1}^{n}x_{k}\sin{k})^2\le (2+\frac{n}{4})\...
Too long for a comment. Let us consider for $X\in \mathbb S^{n-1}$,
$
\langle X,(e^{i \alpha k})_{1\le k\le n}\rangle_{\mathbb C^n}.
$
The question at hand is
$$
\max_{X\in \mathbb S^{n-1}}\vert\langl …
1
vote
A generalization of discrete Hilbert's transform (Montgomery's inequality)
Let me deal with a continuous situation. Let $\lambda:\mathbb R\rightarrow\mathbb R$ be an increasing $C^1$ diffeomorphism and let $u,v$ be in $L^2(\mathbb R)$. We have with $\phi=\lambda^{-1}$,
$$
A= …
1
vote
2
answers
221
views
Logarithmic Sobolev embeddings
Is there a clear connection with Gross' logarithmic Sobolev inequalities? …
0
votes
Logarithmic Sobolev embeddings
Following Christian Remling suggestion, it seems that
$$
\Vert u\Vert_{L^\infty(\mathbb R^d)}\le \gamma(d)\bigl\{
\Vert u\Vert_{L^2(\mathbb R^d)}+
\Vert \vert D\vert^{d/2} L(\vert D\vert) u\Vert_{L^2( …
5
votes
1
answer
371
views
Generalization of Gagliardo-Nirenberg Inequality
The standard Gagliardo-Nirenberg Inequality is
$$
\Vert u\Vert_{L^{\frac{n}{n-1}}(\mathbb R^n)}\le C_n \Vert \nabla u\Vert_{L^{1}(\mathbb R^n)},
\tag{$\ast$}$$
and constitutes a key step to proving So …
8
votes
1
answer
530
views
Inequality for Laguerre polynomials
Let $L_n$ be the $n$-th Laguerre polynomial defined by
$\quad
L_n
(x)=\frac{e^x}{n!}\frac{d^n}{dx^n}(x^n e^{-x}).\quad
$
I want to prove that
$$
\forall n\in \mathbb N,\forall x\ge 0,\quad \sum_{0\le …
2
votes
Is $1/\max(i,j)$ a bounded matrix on Hilbert spaces?
On $\ell^p(\mathbb N^*)$, $1<p<+\infty$, the matrix
$$
A=\left(\frac{1}{i+j}\right)_{1\le i,j},\tag 1
$$
is a bounded operator and since the entries are positive and "equivalent" to your matrix, the …
0
votes
Accepted
An interpolation inequality.
$$
g(\epsilon)=\sum_{k\ge 1} k^se^{\frac {k-1}2\ln(1-\epsilon)}
\lesssim \int_0^{+\infty} x^s e^{-a\epsilon x} dx=
\int_0^{+\infty}x^s e^{-ax}dx\epsilon^{-s-1}
$$
where $a$ is a fixed constant. So
$$ …
2
votes
Gronwall estimate with a Fourier transform
I will more comfortable with the notation $v_\epsilon=\hat{u_\epsilon}$; you have then
$$
v_\epsilon(t,x)=\alpha(t,x)+\int_0^t\int e^{2πix(\xi+\epsilon\phi(s,\xi))} \hat{v_\epsilon}(s,\xi) d\xi ds=\al …
4
votes
(sharp)Garding's inequality and inequality with lower bounds
Let us start with a short review of the so-called G{\aa}rding's inequality. Let $a\in S^m$ be nonnegative. Then with $a^w$ standing for the Weyl quantization of the Hamiltonian $a$,
$$
(1)\quad m=1\qu …