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Ordinary or partial differential equations. Delay differential equations, neutral equations, integro-differential equations. Well-posedness, asymptotic behavior, and related questions.
1
vote
Accepted
Solution of a second order nonlinear ode
Solving the linear first-order
$$
h'=h K^{1/2}e^{f/2}/\sqrt 2
\tag{$\ast$}$$
makes the rhs to vanish. We get then
\begin{align}
2h''-f'h'-Ke^f h&=h' K^{1/2}e^{f/2}\sqrt 2+h K^{1/2}e^{f/2}f'(\sqrt 2)^{ …
4
votes
Accepted
How do I solve this nonlinear ODE with a fractional order term
I understand that your ODE is one-dimensional: in that case you can avoid Lipschitz continuity and replace it by transversality:
The autonomous equation
$$
\dot x =f(x),\quad x(0)=x_0,
$$
has a uniqu …
3
votes
General systems of linear differential equations with variable coefficients
Forget about finding a closed analytical expression for the fundamental matrix. Think about the simple case of a second order scalar equation such as the Airy equation $\ddot x=tx.$
There is neverthe …
0
votes
Dealing with a Matrix ODE in integral form
A simple local existence theorem in a Banach space setting. Let $E$ be a Banach space, $I$ be an interval of $\mathbb R$, $\Omega$ be an open subset of $E$,
$F:I\times \Omega\longrightarrow E$ be a co …
1
vote
Dealing with a Matrix ODE in integral form
Overkill...If $x,y$ are solutions, we get
$$
\vert x(t)-y(t)\vert\le\vert x(0)-y(0)\vert+ \int_{0}^{t}\Vert A(s)\Vert\vert x(s)-y(s)\vert ds=R(t)
$$
and
$
\dot R(t)=\Vert A(t)\Vert\vert x(t)-y(t)\vert …
1
vote
First Order PDE Solution Method Issues
Let me work with $n$ dimensions: you want to study the vector field
$$
X=\sum_{1\le j\le n} a_j(x)\frac{\partial}{\partial x_j},
\tag {1}$$
and in particular find the so-called first integrals of $X$ …
7
votes
1
answer
248
views
On Integrals of the Airy function
Let $Ai$ be the classical Airy function and let $(a_j)_{j\ge 1}$ be the strictly decreasing sequence of its zeroes: we have $a_{j+1}<a_j<\dots <a_2<a_1<0$, $\lim_{j\rightarrow +\infty}a_j=-\infty$. I …
4
votes
second order operator with real coefficients and not locally solvable
The operator $\frac{\partial}{\partial t}+t\Delta_x$ is not locally solvable near $t=0$. It could be seen as a quasi-homogeneous version of Mizohata operator $D_t+it\vert D_x\vert$
since its symbol is …
-1
votes
Reference request: a singular differential equation
Your equation falls in the category of regular singular differential equation. Writing your equation as
$$
x z'=a z+g(x,z),
\tag{$\ast$}$$
the singularity is called regular because the exponent of th …
5
votes
1
answer
340
views
A special function solution of a fourth-order ODE
I want to consider the solutions of the following fourth-order ODE:
$$
f^{(4)}(t)+a tf^{(1)}(t)+b f(t)=0,
\tag{$\ast$}$$
where $a,b$ are complex parameters. It turns out that with a Fourier transforma …
2
votes
Leibniz rule for Pseudo-differential operators of negative order
Let $P$ be a pseudodifferential operator with symbol $p(x,\xi)$ belonging to $S^m_{1,0}$ and let $a(x)$ be a $C^\infty$ function. Then the operator $Pa$ defined by $Pa u=P(au)$ is a pseudodifferential …
2
votes
Solving $x\partial_x f = 0$ over distributions
Let us work in $\mathbb R^n$. The distribution solutions of the equation
$$
(x\cdot \partial _x) u=0
$$
are the distributions which are homogeneous of degree 0. Here
$x\cdot \partial_x=\sum_{1\le j\le …
0
votes
The difference between the nonlocal and local conditions problems
I would like to give another example, a very classical one. Consider a smooth open subset $\Omega$ of $\mathbb R^n$ and let $T$ be a smooth vector field tangential to the boundary $\partial\Omega$. Th …
6
votes
0
answers
141
views
Lagrangean uniqueness versus Eulerian uniqueness
(1) Lagrangean description. Let us consider a $N\times N$ system of autonomous ODE:
$$
\dot x=a(x),\quad \mathbb R\ni t\mapsto x(t)\in \mathbb R^N,\quad a:\mathbb R^N\rightarrow \mathbb R^N.
$$
Instea …
4
votes
Examples of potentials for which Schrödinger equation lacks discrete points in continuous sp...
Consider the (stationary) Schrödinger equation
$$
-\Delta u+ Vu=0,
$$
or the differential inequality
$\vert\Delta u \vert\le \vert V u\vert$, where $V$ is some "potential" function. The following uniq …