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For questions about coalgebras, comultiplication, cocommutativity, counity, comodules, bicomodules, coactions, corepresentations, cotensor product, subcoalgebras, coideals, coradical, cosemisimplicity, ...

2 votes

Equivalent definitions of pro-unipotent coalgebras

What you call "pro-unipotent coalgebras" are called "pointed irreducible coalgebras" in classical M.E. Sweedler's book "Hopf algebras" (W.A. Benjamin, New York, 1969), Section 8.0. … I call them "conilpotent coalgebras"; see e.g. Section 3 of the survey paper https://doi.org/10.1112/blms.12797 . …
Leonid Positselski's user avatar
4 votes
Accepted

Lie coalgebra with no finite-dimensional subcoalgebras

Consider the Lie algebra of vector fields on the formal disk, $\mathfrak g=k[[t]]d/dt$, where $k$ is a field of characteristic zero and $k[[t]]$ is the $k$-algebra of formal Taylor power series in the …
Leonid Positselski's user avatar
1 vote

Morphism of conilpotent coalgebras

Any morphism of coaugmented coalgebras $\phi\colon X\to Y$ preserves the canonical filtrations, i.e., one has $\phi(F_nX)\subset F_nY$ for any morphism of coaugmented coalgebras $\phi$. … Accordingly, you can define a morphism of conilpotent coalgebras $\phi\colon X\to Y$ as an arbitrary morphism of coalgebras $X\to Y$, or if you prefer, as a morphism of coaugmented coalgebras $X\to Y$. …
Leonid Positselski's user avatar
1 vote

Contramodule as direct limit of its finitely generated subcontramodules

So one cannot perform this construction for coalgebras, generally speaking, but only for topological rings. … Still there are plenty of coalgebras $C$ for which the forgetful functor $C{-}\mathbf{contra}\to C^*{-}\mathbf{mod}$ is already fully faithful. …
Leonid Positselski's user avatar
2 votes

Contramodule as direct limit of its finitely generated subcontramodules

But it does hold for surprisingly many infinite-dimensional coalgebras $C$ or topological rings $R$. (In particular, it certainly holds for $C^*=k[[t]]$.) …
Leonid Positselski's user avatar
3 votes

Contramodule as direct limit of its finitely generated subcontramodules

This answer concerns contramodules that are finitely generated as objects of the category of contramodules, in the sense of the abstract category-theoretic definition of "finitely generated". The exa …
Leonid Positselski's user avatar
3 votes
Accepted

$M$ comodule if and only if $N$ and $L$ comodules

For any (coassociative, counital) coalgebra $C$ over a field $k$, there is a fully faithful exact functor from the category of $C$-comodules to the category of $C^*$-modules. The essential image of t …
Leonid Positselski's user avatar
6 votes

Is every dg-coalgebra the colimit of its finite dimensional dg-subcoalgebras?

For coassociative dg-coalgebras over any field $k$ the answer is positive, because: Let $C$ be a $\mathbb Z$-graded coalgebra and $D\subset C$ a finite-dimensional ungraded subcoalgebra (of the underlying … Indeed, even for ungraded coalgebras over a field of characteristic $0$, there is an example of infinite-dimensional Lie coalgebra $L$ having no nonzero finite-dimensional subcoalgebras. …
Leonid Positselski's user avatar
6 votes

Tensor product of coaugmented conilpotent coalgebras

The tensor product of two conilpotent coassociative dg-coalgebras over any field $k$ is a conilpotent coassociative dg-coalgebra over $k$. … Then the question reduces to showing that the tensor product of two conilpotent coalgebras is a conilpotent coalgebra. …
Leonid Positselski's user avatar
2 votes
Accepted

Variant of co-Tor in a bimodule category

I am not sure that I really understand what you want, but I'd say the relevant structure is that of a module category over a monoidal category. Given a monoidal category $\mathcal E$, one can conside …
Leonid Positselski's user avatar
17 votes

Comodule exercises desired

Define a cosimple coalgebra as a coalgebra having no nonzero proper subcoalgebras, and a cosemisimple coalgebra as a direct sum of cosimple coalgebras. …
Leonid Positselski's user avatar
2 votes

In which categories is every coalgebra a sum of its finite-dimensional subcoalgebras?

Let us replace "dualizable" with "Noetherian". Then, I believe, for any locally Noetherian Grothendieck (abelian) category with an exact, associative tensor product functor preserving direct limits ( …
Leonid Positselski's user avatar
15 votes
Accepted

Algebraic geometry for cocommutative corings with counit.

So the category of coalgebras over a field k is the category of ind-objects in the category of finite-dimensional coalgebras, while the latter is the opposite category to the category of finite-dimensional … sum of the coalgebras sitting at the points of this set. …
Leonid Positselski's user avatar