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6 votes

Are there noncongruence subgroups (of finite index) of the modular group generated only by 2...

I've compiled my serial comments on Misha's answer with this new answer, not containing any information unavailable in the other answers, but working out Wohlfart's example mentioned by Agol in more e …
Lee Mosher's user avatar
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18 votes

Subgroups of $SL_2(\mathbb R)$ which contain $SL_2(\mathbb Z)$ as a finite index subgroup

$G = SL_2(\mathbb{Z})$ is indeed the only possibility. This follows from the structure of the quotient orbifold $\mathcal{O} = \mathbb{H}^2 / SL_2(\mathbb{Z})$, which is a once-punctured sphere with a …
Lee Mosher's user avatar
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