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Homotopy theory, homological algebra, algebraic treatments of manifolds.
40
votes
Accepted
Connected sum of topological manifolds
In the topological category the proof that connected sum is well-defined depends on the Annulus Theorem, first proved by Kirby; the necessity of the Annulus Theorem is seen from Bruno Martelli's answe …
28
votes
Occurrences of (co)homology in other disciplines and/or nature
My understanding, from conversations with Raoul Bott, is that his early work on electrical circuits and the Bott-Duffin theorem can be intepreted as exhibiting close connections between de Rham cohomo …
19
votes
Fundamental groups of noncompact surfaces
I just ran across this question, and thought I would give a precise version of the proof Ilya suggested. I believe I learned this proof in Richie Miller's topology course, Michigan State University, 1 …
15
votes
Accepted
Universal covering of compact surfaces
You can build a certain covering space of the surface $S$ rather explicitly as a nested union of closed discs $D_1 \subset D_2 \subset D_3 \subset \cdots$, each contained in the interior of the next, …
14
votes
Why is the fundamental group of a compact Riemann surface not free ?
Riffing off of Ben Steinberg's answer, which amounts to the statement that a tree is not quasi-isometric to the hyperbolic plane, here's a proof which doesn't require knowing anything about ends.
Til …
13
votes
When can a class in $H^1(M;\mathbb{Z})$ be represented by a fiber bundle over $S^1$
If $M$ is a compact and irreducible 3-manifold, one answer is provided by a theorem of Stallings, in his 1962 paper "On fibering certain 3-manifolds": $\alpha$ is represented by a fibration $f : M \to …
13
votes
Compelling evidence that two basepoints are better than one
In my proof that mapping class groups are automatic, Ann. of Math. (2) 142 (1995), no. 2, 303–384, I used a theorem from ECHLPT "Word Processing in Groups" which says that if a groupoid is automatic …
9
votes
Orbifold fundamental group in terms of loops?
To understand the difficulties inherent in forming a "path-based" definition of the orbifold fundamental group, it is good to ponder Serre's definition of a fundamental group of a graph of groups, giv …
9
votes
The fundamental group of a closed surface without classification of surfaces?
I will answer the question of whether this also gives the classification cheaply.
No.
It gives the classification at the expense of proving that every surface group has a free cocompact action on th …
8
votes
Manifolds covered by an n-dimensional torus
Assuming that you DO mean that $T^n$ is a finite sheeted covering space, at the very least one can say that $\pi_1(M)$ is a torsion free $n$-dimensional crystallographic group. This follows from the B …
6
votes
The relationship between low dimensional topology and dynamics
The machinery of Markov partitions and stable/unstable foliations for Anosov and Axiom A diffeomorphisms was adapted to several different bits of low dimensional topology. In the Nielsen-Thurston clas …
5
votes
How to get convinced that there are a lot of 3-manifolds?
Read Chapter 4 of Thurston's notes http://library.msri.org/books/gt3m/. He produces infinitely many closed hyperbolic 3-manifold of different volumes, and hence non-homeomorphic, just by doing Dehn su …
5
votes
Uniquely geodesic and CAT(0) spaces?
A good counterexample is the Teichmuller space of a closed oriented surface $S$. It is uniquely geodesic by Teichmuller's theorem, but it is not $CAT(0)$.
5
votes
Accepted
Nielsen-Thurston classification of homeomorphisms for open surfaces?
The theories for an open surface $S$ and for a compact surface with boundary $\overline S$ whose interior is identified with $S$ are the same. The inclusion of $S$ into $\overline S$ defines an isomor …
5
votes
Jordan curve theorem for cylinders
If you are willing to quote the Schoenflies theorem and the classification of surfaces, a quick proof of this result is a standard exercise. First, using algebraic topology (as in the proof of the Jor …