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28
votes
Accepted
Recent claim that inaccessibles are inconsistent with ZF
As I pointed out in the meta thread, this question overlaps with a bunch of older MO questions.
Arguments against large cardinals
Nonessential use of large cardinals
Inaccessible cardinals and Andre …
5
votes
Collapsing cardinals before the first inaccessible
This product forcing (known as the Lévy collapse) is not ${<\kappa}$-closed for any $\kappa > \omega$ since the individual factors $P_\alpha$ are not ${<\kappa}$-closed. The forcing is $\lambda$-c.c., …
19
votes
On statements independent of ZFC + V=L
This is a very interesting question. Here is what Shelah says about this in The Future of Set Theory:
ISSUE: Where does the truth lie between the following two extremes
Every combinatorial statement …
4
votes
What notions of universe does predicative type theory admit?
The analogy between universes in type theory and the Mahlo hierarchy in set theory has been analyzed in many different ways by Michael Rathjen. (This builds on his analysis of KPM, but ML type theorie …
15
votes
Large cardinal axioms and Grothendieck universes
It is very near the bottom of Kanamori's chart. The very bottom of the chart is the level of a (strongly) inaccessible cardinals, which is the smallest large cardinal axiom. Right above the inaccessib …
3
votes
failure of $\square(\kappa)$ at an inaccessible $\kappa$
In general, one cannot force the failure of $\square(\kappa)$ at a fixed cardinal $\kappa$. Indeed, if $\kappa$ is any regular uncountable cardinal which is not weakly compact in $L$, then there is a …
23
votes
Accepted
Applications of infinite Ramsey's Theorem (on N)?
The following fact has been called "Ramsey's Theorem for Analysts" by H. P. Rosenthal.
Theorem. Let $(a_{i,j})_{i,j=0}^\infty$ be an infinite matrix of real numbers such that $a_i = {\displaystyle …
4
votes
When is $A$ "$L$-ish" whenever $B$ is "$L$-ish"?
Here is an extension of Barwise's theorem which may be of some use.
Theorem. Fix a real $a \subseteq \omega$ in $W$. Suppose the preorder $\preceq$ is first-order definable with parameter $a$ and that …
33
votes
Reasons to believe Vopenka's principle/huge cardinals are consistent
It should be noted that Petr Vopěnka himself did not believe in the principle! Here is the story, taken from Adámek and Rosický Locally Presentable and Accessible Categories (p. 278-279).
The stor …