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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
9
votes
2
answers
456
views
Converse to basic result on prime decomposition
We know that in a normal extension of number fields $L/K$, for any prime $P$ of $K$ and any primes $Q_1,Q_2$ of $L$ lying over $P$, the ramification indices and inertial degrees are the same,
$$e(Q_1| …
1
vote
Integer subset that only occupies (p-1)/2 equivalence classes mod p?
Here is something I noticed - no idea if it helps:
Suppose $A\subset\mathbb{Z}$ has the property that for each odd prime $p$ and $\phi_p:\mathbb{Z}\rightarrow\mathbb{Z}/p\mathbb{Z}$, we have $|\phi_p …
0
votes
Accepted
Interpreting Euler's Criterion for Idoneal Numbers
In the remark below the statement of Euler's criterion in the paper you linked to, notice that Grube, who tried to correct Euler's original "proof" of this criterion, actually only provided a correct …
0
votes
Representing numbers in a non-integer base with few (but possibly negative) nonzero digits
Your proof looks right to me. As a smaller example, a number with a Zeckendorf representation with 7 terms is 609 = 377 + 144 + 55 + 21 + 8 + 3 + 1 (note that 609 = 610 - 1); I believe it is impossibl …
0
votes
a weird sequence with a non-integral term
My 2 cents (ha ha): perhaps the approach is to show that the power of 2 dividing $2+\sum_{i=1}^{n-1}a_i^2$ is eventually less than the power of 2 in $n$, and that this somehow involves looking at $a_{ …
17
votes
Accepted
trace zero elements in algebraic number fields
The answer is no. Let $\alpha\in\mathbb{C}$ be a root of $x^3+tx+1$ for $t\in\mathbb{Q}\setminus\mathbb{Z}$, and let $L=\mathbb{Q}(\alpha)$, so that $N_\mathbb{Q}^L(\alpha)=1$ and $tr_{\mathbb{Q}}^L(\ …
13
votes
2
answers
2k
views
Are the field norm and trace the unique "nice" maps between fields?
This seems like an obvious fact, but I'm not sure what the necessary meaning of "nice" is to get a result like this. I'm wondering if there is a theorem of the form:
For any <1> field extension $K/F …
2
votes
3
answers
1k
views
Generalization of primitive roots
The standard definition is that $a\in\mathbb{Z}$ is a primitive root modulo $p$ if the order of $a$ modulo $p$ is $p-1$.
Let me rephrase, to motivate my generalization: $a\in\mathbb{Z}$ is a primitiv …
8
votes
What is the p-adic valuation of a number?
The conflict is just that some people use the words valuation and absolute value interchangeably. The term "p-adic valuation", used correctly, refers to $\nu$, though perhaps in some areas of math the …
54
votes
Accepted
Are some numbers more irrational than others?
Yes, there is such a thing as the irrationality measure of a real number (I'm not sure if it can be / has already been extended to complex numbers). It is based on the idea that all algebraic numbers …
2
votes
Teach a course in 1 month
I think Jones + Jones
http://www.amazon.com/Elementary-Number-Theory-Gareth-Jones/dp/3540761977
would be a good all-around introduction. It has solutions to every problem in the back, which can be …
0
votes
Expressing field inclusions by polynomial equalities on coefficients
So, equivalently, suppose we have a symmetric function $S( , , , )$ such that $S(z_1,z_2,z_3,z_4)=0$ whenever $z_1,z_2,z_3,z_4$ are conjugates over $\mathbb{Q}$ and such that $\mathbb{Q}(z_i)\supset\m …
11
votes
Calculating Pisano periods for any integer
It depends on what you mean by "calculate".
If you want a "closed-form" expression for $k(m)$, the period of the Fibonacci sequence modulo $m$: One should expect that there is no such thing, because …
6
votes
3
answers
971
views
Factorization of elements vs. of ideals, and is being a UFD equivalent to any property which...
Why exactly is the unique factorization of elements into irreducibles a natural thing to look for? Of course, it's true in $\mathbb{Z}$ and we'd like to see where else it is true; also, regardless of …
5
votes
Polynomial representing all nonnegative integers
If we can make a (single variable) polynomial function $g(x)$ from $\mathbb{Z}$ onto $\mathbb{N}$, we could compose it with the Cantor pairing function, but such a $g(x)$ seems implausible for some re …