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Complex analysis, holomorphic functions, automorphic group actions and forms, pseudoconvexity, complex geometry, analytic spaces, analytic sheaves.
5
votes
Accepted
How can one test whether a given analytic curve in the plane is algebraic or not?
Let $\Gamma$ be a non-algebraic analytic curve. Let $z_1,\dots, z_n$ be points of $\Gamma$. Let $X_{n,d}$ be the set of algebraic curves of degree $d$ that contain $z_1,\dots, z_n$. Now consider a ran …
17
votes
Accepted
For which rationals is this exponential sum bounded?
As Fedor Petrov expects in the comments, this is true for $x=a/b$ if and only if the order of $2$ modulo $b$ is greater than the order of $2$ modulo the product of prime factors of $b$.
To prove this, …
7
votes
Size of $\zeta'(s)$ at its zeros
Bounds for the value of zeta take the form $$ |\zeta(\sigma +it) | \ll t^{ f(\sigma)+\epsilon} $$ where $|t|>2$ and $f$ is some function of $\sigma$. We can take $f(1)=0$ and $f(0)=1/2$ and we can al …
14
votes
Accepted
Analytic continuation gives a covering space (and not just a local homeomorphism)
Consider the map $f\colon z \mapsto z^3-z$. Then there is a path component $M$ of $\mathcal G$ consisting of germs of the inverse map to $f$. More precisely $M$ is isomorphic to $\mathbb C \setminus \ …
7
votes
Accepted
Dirichlet Series that fail to be L-functions
If $f(z)$ is a holomorphic function in a neighborhood of $z=0$ then $f( p^{-s})$ is a Dirichlet series for any prime (or really any natural number) $p$: we take $a_n=0$ if $n$ is not a power of $p$ an …
3
votes
Accepted
Reference request and clarification for Central Limit Theorem for complex random variables
On the "Furthermore":
The central limit theorem for vectors involves the variance-covariance matrix. Let $Z = X+iY$ be a complex random variable (with mean $0$ for simplicity). If $X,Y$ have variance- …
6
votes
Bounding minimal absolute value of a point on a complex algebraic variety
No (for one interpretation of the question). There does not exist a continuous function $b $ from the set of systems of polynomial equations to $\mathbb R^{>0} \cup \{\infty\}$ that takes a finite val …
2
votes
Accepted
Threefolds with Kodaira dimension 2 and non-isotrivial Iitaka map
Here is a way to construct such threefolds.
Take $E \to \mathbb P^1$ a non-isotrivial elliptic surface. Take $S$ another surface, say a general type surface. Any rational function on $S$ gives a ratio …
20
votes
Heuristic argument for the Riemann Hypothesis
The function field model came up in GH from MO's answer, and then also in user54038's. I just want to add some detail to explain how good of an analogy the function field model is.
The Riemann zeta …
7
votes
Accepted
On some analytic property of the Riemann zeta function
$$\int_x^\infty \{ u\} u^{-s-1} du = \int_x^\infty \left( \{ u\}-\frac{1}{2}\right) u^{-s-1} du + \frac{1}{2} \frac{x^{-s}}{s}$$ and by integration by parts,
$$\int_x^\infty \left( \{ u\}-\frac{1}{2} …
9
votes
Accepted
Generating series of rational$\times \exp($rational$)$
We have $$ \frac{d}{dx}\left ( f(x) e^{h(x)}\right) = \left( \frac{ f'(x)}{f(x)} + h'(x) \right) \left( f(x) e^{h(x)}\right).$$
Thus
$$ \sum_n a_n n x^{n-1} = \left( \frac{ f'(x)}{f(x)} + h'(x) \rig …
5
votes
Analytic continuation of Euler product $\prod_{p} (1 - e^{-2 \pi i p \alpha}p^{-s})^{-1}$
Suppose $\alpha = a/b$ is rational. All but finitely many primes are relatively prime to $b$. For these primes, we have $$ e^{ 2\pi i ap/b} = \sum_{\chi: (\mathbb Z/b)^\times \to \mathbb C^\times} \c …
14
votes
Tate's definition of residues
Residues satisfy $$\operatorname{res}_x(fdg) + \operatorname{res}_x(gdf) = \operatorname{res}_x(d (fg)) =0$$
which tells you that they are antisymmetric, and many antisymmetric pairings in math arise …
10
votes
Accepted
Status of Hodge conjecture over subrings of $\mathbb{C}$
The $k$-Hodge conjecture is false for any $k$ containing an irrational real $\alpha$.
Indeed we may clearly assume $\alpha$ is negative. Consider the elliptic curve $E = \mathbb C / \langle 1, \sqrt{ …
3
votes
Holomorphic maps into a symmetric product of Riemann surface
As SashaP already pointed out, this is false. In fact it fails very badly: The space of non-constant holomorphic maps from $X$ to $\operatorname{Sym}^2 Y$ can already contain infinitely many connected …