Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 17836

Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.

4 votes

If $X$ is compact, is $[X]^2$ compact, too?

If $[X]^2$ is compact then $X$ is finite. Let $\Delta \subseteq X^2$ be the diagonal. It is easy to show that the map $X^2 \setminus \Delta \to [X]^2$ given by $(x,y) \mapsto \{x,y\}$ is continuous, …
Ramiro de la Vega's user avatar
12 votes
Accepted

Hausdorff space $X$ with $X\cong [X]^2$

It is easy to see that the operation $X \mapsto [X]^2$ preserves the properties: countable, second-countable, regular, no isolated points. Hence $\mathbb{Q} \cong [\mathbb{Q}]^2 $.
Ramiro de la Vega's user avatar
12 votes
Accepted

"Productively normal" space

The answer is no. It was proved by Mary Ellen Rudin in $\aleph$-Dowker spaces (1978) that for any non-discrete Hausdorff space $S$ there is a normal Hausdorff space $N$ such that $S\times N$ is not no …
Ramiro de la Vega's user avatar
3 votes

Binary relations as the topological closure of the diagonal

According to this article of Colasante and Van Der Zypen, it is an open problem to characterize those reflexive and symmetric relations for which there is such a topology. If we restrict ourselves to …
Ramiro de la Vega's user avatar
4 votes
Accepted

Universality with respect to quotients

The answer is no, by the argument given by Henno in his comment. It true that there are exactly $2^{2^\kappa}$-many non-homeomorphic topologies on a set of size $\kappa \geq \aleph_0$. See for example …
Ramiro de la Vega's user avatar
7 votes
Accepted

When is the topology generated by countable subsets?

A space $X$ is said to have countable tightness if whenever $A \subseteq X$ and $p\in \bar{A}$, there is a countable $B \subseteq A$ such that $p \in \bar{B}$. It is not hard to see that a space has c …
Ramiro de la Vega's user avatar
17 votes
Accepted

Strongly rigid Hausdorff spaces

Yes, see for example "Continua which admit only the identity mapping onto non-degenerate subcontinua" by H. Cook (Fund. Math. 60, 1967, 241-249).
Ramiro de la Vega's user avatar
0 votes
Accepted

A question on compact sets

This is an attempt to formalize Christian Remling´s idea. Cover $K$ by finitely many balls $\{B(x,r_x): x \in S \}$ such that $\overline{B(x,2r_x)} \subseteq U_x$. Let $\delta$ be the minimum of the …
Ramiro de la Vega's user avatar
7 votes

Existence of injective neighborhood selection function as separation axiom

A space is $T_{1/2}$ if every singleton is either open or closed. Sierpinski's space is an example of a $T_{1/2}$ not $T_1$ space. If $X$ is a $T_{1/2}$ space, let $A$ be the set of non-isolated point …
Ramiro de la Vega's user avatar
6 votes
Accepted

Which compacta contain copies of Cantor cubes?

It was proved independently by Efimov and Gerlits that the answer is yes if $\kappa$ has uncountable cofinality. In fact they proved this for any dyadic $X$ (it is well known that Dugundji compacta ar …
Ramiro de la Vega's user avatar
2 votes
Accepted

Maximal discrete subsets of connected $T_2$-spaces

No. If $S$ is a maximal discrete subset of a $T_1$-space $X$, then every point of $S$ is isolated in $X$ (in fact, $S$ must be the set of isolated points of $X$ and it must be dense in $X$). Thus if $ …
Ramiro de la Vega's user avatar
2 votes
Accepted

A space with countable tightness which is not a Fréchet space?

First note that in a space with countable tightness: $P$-point $\Leftrightarrow$ weak $P$-point $\Leftrightarrow$ Isolated point. So you are looking for a point for which every deleted neighborhood c …
Ramiro de la Vega's user avatar
6 votes

Is there a linearly Lindelöf non-Lindelöf $P$-space?

It was shown by A.K. Misra in "A topological view of $P$-spaces" that any regular $\aleph_1$-Lindelöf $P$-space is normal (see Corollary 4.6). Also, it is not hard to see that any linearly Lindelöf sp …
Ramiro de la Vega's user avatar
7 votes

Nonmetrizable compact totally disconnected spaces without isolated points

The boolean algebra of clopen subsets of a space satistying conditions 1,2 and 3 is always a base for the topology (i.e. the space is zero-dimensional). So the space is homeomorphic to the Stone space …
3 votes
Accepted

A question about small cardinals related to Michael's Problem

It is not true that if $\mathscr{F}$ is dominating then $\{K_f:f\in\mathscr{F}\}$ is a cover of $\omega^\omega$. For example it is possible to have a dominating $\mathscr{F}$ such that $f(4)=6$ for ev …
Ramiro de la Vega's user avatar

1
2 3 4 5
8
15 30 50 per page