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Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.
7
votes
1
answer
1k
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Haar measure on infinite dimensional Lie groups?
Hi. Is there a Haar measure or equivalent on infinite dimensional Lie groups? I've been playing around with $Diff(S^1)$, and at least a direct approach seems quite hopeless. It goes something like thi …
3
votes
Software for Computing Baker-Campbell-Hausdorff
You don't need any packages to be able to do that in Mathematica for small Lie algebras such as su(2), probably not in SAGE either (I'm familiar with Mathematica). Anyway, Basically you just need to u …
5
votes
1
answer
470
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Finite dimensional homogeneous spaces of $Diff(S^1)$
This question is a refined version of Representations of infinite dimensional Lie algebras as vector fields on manifolds
I'm interested in the finite dimensional homogeneous spaces of $Diff(S^1)$. Th …
5
votes
Why the Gell-Mann matrices in the SU(3)-model need to be trace orthogonal ?
It's just a choice of a basis. Compare it to an orthogonal vector basis. And please... try to write math in LaTeX :) (see the "How to write math" box on the right and below).
1
vote
1
answer
289
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Exterior differential system on $SO(3;\mathbb R) \times \mathbb R$
I have the following exterior differential system for one forms $\alpha, \beta, \gamma$, where the $\theta^i$ are a cotangent basis on $SO(3)$, i.e. they satisfy $d \theta^i = \epsilon_{ijk} \theta^j …
6
votes
1
answer
649
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ANOTHER Exterior differential system on $SO(3;\mathbb R) \times \mathbb R$
I have another exterior differential system for one forms $U^i$, where the $\theta^i$ are a cotangent basis on $SO(3)$, i.e. they satisfy $d \theta^i = \epsilon_{ijk} \theta^j \wedge \theta^k$ for the …
2
votes
1
answer
364
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Variant of the Riemann Mapping Theorem for $Conf(\mathbb H^2)$?
According to the Riemann mapping theorem it is possible to map a simply connected open subset $B \subset \mathbb C$ into any other $B' \subset \mathbb C$ by a (bi-)holomorphic mapping. Moreover, such …