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9
votes
2
answers
462
views
Relation between $\neg \square(\kappa)$ and the tree property at $\kappa$.
If $\kappa$ is an inaccessible cardinal then the tree property at $\kappa$ is equivalent to weak compactness of $\kappa$, which implies that $\square(\kappa)$ fails---that is, that every coherent sequ …
5
votes
2
answers
613
views
A weak (?) form of Shelah cardinals
The following definition of a large cardinal property combines parts of the definitions of "Shelah cardinal" and "Woodin cardinal":
A cardinal $\kappa$ is weakly Shelah if for all $f : \kappa \to \ka …
10
votes
0
answers
331
views
Absoluteness of "$\kappa$-homogeneously Suslin" for sets of reals
What is known about the absoluteness, or lack thereof, of the notion of "$\kappa$-homogeneously Suslin" for sets of reals?
For example, if $A$ is $\kappa$-homogeneously Suslin and $\lambda > \kappa$ …
13
votes
1
answer
437
views
Does this consequence of measurability in terms of games of length $\omega+1$ imply measurab...
For any two structures $\mathcal{M}$ and $\mathcal{N}$ in the same first-order language $\mathcal{L}$ and any ordinal $\theta$, let $G_\theta(\mathcal{M},\mathcal{N})$ be the two-player game of perfec …
9
votes
1
answer
581
views
Can $\omega_1$ be supercompact?
Is "ZF + $\omega_1$ is supercompact" consistent relative to "ZFC + there is a supercompact cardinal"?
In particular, if $\delta$ is supercompact, does it remain so in $V(\mathbb{R} \cap V[G])$ where …
9
votes
0
answers
291
views
ZF + "every Suslin set of reals is ${\bf \Sigma}^1_2$"
What is known about the theory
($\ast$) ZF + "every Suslin set of reals is ${\bf \Sigma}^1_2$"?
By "reals" I mean elements of the Baire space $\omega^\omega$. For a cardinal $\kappa$, a set of rea …
6
votes
2
answers
386
views
Measures that are not OD
Is anything known about the consistency strength of the statement:
"There is a normal measure (on a cardinal) that is not ordinal-definable"?
In particular, is it consistent relative to the existenc …
6
votes
2
answers
434
views
Stationary many subsets of $\kappa^+$ whose order type is a cardinal and whose intersection ...
Is anything known about the consistency strength of the following statement?
$\kappa$ is a Mahlo cardinal and there is a stationary set of $a \in \mathcal{P}_\kappa(\kappa^+)$ such that $a \cap \kap …
17
votes
2
answers
1k
views
Can measures be added by forcing?
The Lévy-Solovay theorem says that small forcings do not create measures. J.D. Hamkins has generalized this to a larger class of forcings called gap forcings. I would assume this cannot be generaliz …
9
votes
1
answer
624
views
Homogeneous Namba-like forcing
Let $\kappa \ge \aleph_3$ be a regular cardinal that is countably closed ($\alpha^\omega < \kappa$ for every $\alpha < \kappa$.) I'm mostly interested in the case that $\kappa$ is strongly inaccessib …
7
votes
0
answers
238
views
Countable choice in $L(\mathbb{R}^*_G)$
Let $\lambda$ be a singular strong limit cardinal and let $G \subset \text{Col}(\omega,\mathord{<}\lambda)$ be a $V$-generic filter. Let $\mathbb{R}^*_G = \bigcup_{\alpha < \lambda} \mathbb{R}^{V[G \ …
6
votes
0
answers
446
views
Inaccessible cardinals and the perfect set property for coanalytic sets
I am wondering who proved the following fact:
($\ast$) If $\omega_1$ is not inaccessible in $L$, then there is an uncountable coanalytic set of reals without a perfect subset.
I have been unable to …
4
votes
1
answer
196
views
A version of the Martin–Solovay tree for $H_\kappa$
Consider a fixed $\Pi^1_2$ property of reals, $A(x)$.
Is it true that relative to a regular cardinal $\kappa$, one can define a version of the Martin–Solovay tree $T_2$ for $A$ with the following pro …