Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Theory and applications of probability and stochastic processes: e.g. central limit theorems, large deviations, stochastic differential equations, models from statistical mechanics, queuing theory.
0
votes
Stopping time of a Markov chain
I think I did manage to get something useful in five phases. With high probability,
1) $A=1$ to $A\in(\frac{n}{6},\frac{2n}{3})$ in $\log_2{n}\pm 1$ rounds,
2) $A=an$ to $A=dn$ for some $0< d <<1$ i …
3
votes
3
answers
2k
views
Stopping time of a Markov chain
Let $A(t+1)=A(t)+Bin(n-A(t),\frac{A(t)}{n})$ with $A(0)=1$ and let $T_n$ be the minimum of $t$ such that $A(t)=n$.
I think that $A(t)$ should behave like the naive deterministic approximation $a(t+1) …