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Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.

1 vote

nontrivial isomorphisms of categories

Stone's representation theorem gives you an isomorphism between every Boolean algebra and a field of sets. Viewed categorically, this is an isomorphism of categories, since isomorphism and equivalence …
Neel Krishnaswami's user avatar
2 votes

Kleisli Monad bijection

This didn't fit in the comments, so I'm posting it as an answer. Ignoring size issues, we can define a category as a set of objects, together with a family of sets of morphisms, with one set for eac …
Neel Krishnaswami's user avatar
3 votes
Accepted

approximating categories with continuous functors

As it happens, I just saw a paper about this very subject today -- Martin Hyland's "Some Reaons for Generalizing Domain Theory", which is concerned with precisely the generalization you suggest, in or …
Neel Krishnaswami's user avatar
8 votes

Using ends to construct categorical fixed points

Hi Todd, I was hoping that someone more knowledgeable than me would answer this question, but since that hasn't happened yet I'll post a few comments. As you probably already know, your observation …
Neel Krishnaswami's user avatar
13 votes
Accepted

"Linked List" puzzle

The theory of species is the full answer to your question -- but in this specific case all that is needed are some very basic properties of polynomial functors. Let's focus on you fixed-point equatio …
Neel Krishnaswami's user avatar
6 votes

Freyd cover of a category.

Freyd covers are a fundamental tool in the semantics of programming languages. Here, the technique is called "logical relations" or sometimes "Tait-Girard reducibility candidates". The general idea …
Neel Krishnaswami's user avatar
5 votes

A functor whose initial algebra is another's terminal coalgebra

Here's a sequence of answers. The set of streams of elements of $A$ can be thought of as the final coalgebra $\nu F$ of the functor $F(X) = A \times X$. It is also the initial algebra of the functo …
Neel Krishnaswami's user avatar
2 votes

Do non-associative objects have a natural notion of representation?

For monoids (which are associative) the Krohn–Rhodes theorem gives a powerful decomposition result: every finite monoid is a quotient of a submonoid of an alternating wreath product of finite groups a …
Neel Krishnaswami's user avatar
4 votes

What non-monoidal functors on monoidal categories are used "in nature"?

It seems like many of the standard examples of monads in functional programming can be transported to linear logic to produce examples of non-monoidal functors. E.g., the linear state monad $T_S(A) …
Neel Krishnaswami's user avatar
4 votes
1 answer
411 views

"Category" of Nonempty Metric Spaces and Contractive Maps?

The usual way of getting a category of metric spaces is to take metric spaces as objects, and the nonexpansive maps (ie, functions $f : A \to B$ such that $d_B(f(a), f(a')) \leq d_A(a, a')$) as morphi …
Neel Krishnaswami's user avatar
16 votes
Accepted

Is there a category of non-well-founded sets?

Yes, there is. See Peter Aczel's 1988 notes on models of non-well-founded set theory, here. The basic idea is that you can model sets as graphs (ie, as a collection of element sets together with a bin …
Neel Krishnaswami's user avatar
4 votes
Accepted

Recursively dependent types?

If $z$ is a constant, it's completely unproblematic, but it's troublesome if $z$ is a variable. Here's a simple example: suppose $A$ is a type operator of kind $\mathbb{N} \to \star$, defined as follo …
Neel Krishnaswami's user avatar
3 votes
Accepted

Higher-order, multi-sorted, non purely equational version of universal algebra ?

Lawvere theories generalize to higher-order logic in a straightforward way. A first-order hyperdoctrine is a functor $\mathcal{P} : C^{\mathrm{op}} \to \mathrm{Poset}$ where $C$ has products and is us …
Neel Krishnaswami's user avatar
6 votes

Equality vs. isomorphism vs. specific isomorphism

Natural examples arise in proof theory: if you equate isomorphic propositions, then the semantics of proofs collapses -- all proofs of a given proposition end up having the same denotation. But if y …
Neel Krishnaswami's user avatar
12 votes

Any example of a non-strong monad?

This answer is largely a rendition of Sridhar's comment into lambda calculus. A strong monad $T$ has the following introduction and elimination rules in the lambda calculus. $$ \frac{\Gamma \vdash e …
Neel Krishnaswami's user avatar

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