Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 160378

Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.

8 votes

non-associative but commutative algebra

The class of Jordan algebras are the most important class of algebras in this direction. They are defined by the two identities, (commutativity): $xy=yx$, (Jordan identity): $(xy)(xx)=x(y(xx))$. They …
jg1896's user avatar
  • 3,318
1 vote

Different definitions of the dimension of an algebra

Expanding the last entry on noncommutative transcendence degrees: When your algebra $A$ is prime Goldie (such as Noetherian domains) there are two recent analogues of noncommutative transcendence degr …
jg1896's user avatar
  • 3,318
9 votes

Sufficient conditions for $\mathrm{Der}_k(A)$ to be f.g. projective

For finitely generated domains over a base field $k$ of characteristic 0, we have that if $A$ is regular, then both $Der_k \, A$ and the module of Kähler differentials are finitely generated projectiv …
jg1896's user avatar
  • 3,318
5 votes
1 answer
318 views

Generalizations of Chevalley–Shephard–Todd's Theorem?

Major Edit I will reformulate my question signicantly, given Anton Geraschenko's comment. The old version of the question is bellow. For simplicity, my base field is $\mathbb{C}$. If $G<\operatorname{ …
jg1896's user avatar
  • 3,318
1 vote

Generalizations of Chevalley–Shephard–Todd's Theorem?

I have exchanged e-mail with some specialists on invariant theory and affine algebraic geometry, and here is a summary of what I learned. For the sake of simplicity (although this is by no means neces …
jg1896's user avatar
  • 3,318
2 votes
0 answers
73 views

When is a finitely generated commutative algebra a projective module over its invariant suba...

For the sake of simplicity, I will work over the complex numbers. Let $A$ be a finitely generated algebra and $G$ any finite group of algebra automorphisms. Then, by Noether's Theorem, $A^G$ is also a …
jg1896's user avatar
  • 3,318
4 votes
0 answers
93 views

List of equivalent conditions for the invariant subalgebra to be polynomial

Let $k$ be a field, $P_n$ the polynomial algebra in $n$ indeterminates, and $G<\operatorname{GL}_n$ a finite group whose order is coprime to the characteristic of $k$, and that acts on $P_n$ by algebr …
jg1896's user avatar
  • 3,318