Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 157483

(Co)chain complexes, abelian Categories, (pre)sheaves, (co)homology in various (possibly highly generalized) settings, spectra, derived functors, resolutions, spectral sequences, homotopy categories. Chain complexes in an abelian category form the heart of homological algebra.

15 votes
1 answer
2k views

Has anyone seen this generalization of the snake lemma? Is it useful?

I originally posted this question on MSE (link), but was suggested to post here instead. While learning about spectral sequences a friend of mine found a proof of the snake lemma using spectral seque …
Jacob FG's user avatar
  • 497
6 votes
3 answers
365 views

Is there a finite dimensional algebra with left finitistic dimension different from its righ...

Let $\Lambda$ be finite dimensional algebra over a field $k$. The (left) finitistic dimension of a finite dimensional algebra is defined as $$\operatorname{findim}(\Lambda)=\sup\{\operatorname{pd}M | …
Jacob FG's user avatar
  • 497
3 votes
1 answer
185 views

Explicit proof that algebra is derived wild

Following the terminology of Drozd, Yuriy A., Derived tame and derived wild algebras, Algebra Discrete Math. 2004, No. 1, 57-74 (2004). ZBL1067.16028. let $A$ and $R$ be algebras over a field $k$. A s …
Jacob FG's user avatar
  • 497
2 votes

Is there a finite dimensional algebra with left finitistic dimension different from its righ...

Let $\Lambda$ be the path algebra of the quiver with relations $(a^2, ac, ba, cbc)$. Then I claim $\operatorname{findim}(\Lambda) \geq 1$, while $\operatorname{findim}(\Lambda^{op})=0$. The projectiv …
Jacob FG's user avatar
  • 497
1 vote
Accepted

Explicit proof that algebra is derived wild

A few such examples are constructed in Bekkert, Viktor; Drozd, Yuriy; Futorny, Vyacheslav, Derived tame local and two-point algebras, J. Algebra 322, No. 7, 2433-2448 (2009). ZBL1191.16017.
Jacob FG's user avatar
  • 497