Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with digits
Search options not deleted
user 149083
1
vote
1
answer
369
views
Problem related to inequality of sum of digits of power sum
Let $D$ be the function define as $D(b,n)$ be the sum of the base-$b$ digits of $n$.
Example: $D(2,7)=3$ means $7=(111)_2\implies D(2,7)=1+1+1=3$
Define $S(a,m)=1^m+2^m+3^m+... …
- 599
4
votes
0
answers
446
views
There are infinitely many prime which have arbitrary large gap in their digits in particular...
Motivation: If Claim 1 is true then we can say there exist arbitrary large gaps between digits of prime $\left[\frac{(mt+r)^m}{m}\right]$ in base expansion $mt+r$, because we can express $\left[\frac{( … frac{(mt+r)^m}{m}\right]=\sum_{i=0}^{m-1}(x_it+y_i)(mt+r)^i$$ for some non negative integer $x_i,y_i$ such that $0\le x_it+y_i<mt+r$ then there exists a positive integer $N$ such that $x_it+y_i$ are digits …
- 599