Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 14830

Complex analysis, holomorphic functions, automorphic group actions and forms, pseudoconvexity, complex geometry, analytic spaces, analytic sheaves.

21 votes

Integral of $\log|e^{it}-1|$

Here's another elementary proof, again assuming one has checked that the integral converges absolutely despite the singularity at $t=0$. Let $I$ be the average of the $2\pi$-periodic function $\log \l …
Noam D. Elkies's user avatar
16 votes
Accepted

A statement on complex polynomials

The conjecture is easily seen to be true for $n<3$. We give a counterexample for $n=3$. Let $p_i = z^2 - \omega_i$ where the $\omega_i$ are the cube roots of unity. These are linearly dependent becaus …
Noam D. Elkies's user avatar
8 votes
Accepted

Modular form not meromorphic at $\infty$

[expanding on my comment to convert it to an answer] An example is $e^j \varphi$ where $j$ is the $j$-invariant and $\varphi$ is any nonzero form of weight $k$. In general a holomorphic (or meromorphi …
Noam D. Elkies's user avatar
4 votes
Accepted

A generalization of polynomial algebra on a Riemann surface

Counterexample to the first question ("is $A$ an algebra of functions?"): Let $M$ be a vertical strip such as {$x + iy : 0 < x < 1$}, and define $f_1,f_2$ as the restriction to $M$ of the entire func …
Noam D. Elkies's user avatar
4 votes
Accepted

Sums of entire surjective functions

One expects there to be no such $a_n$ in general, because the "typical" entire functions is surjective (those that aren't are of the special form $z \mapsto c + \exp g(z)$). An explicit example is $ …
Noam D. Elkies's user avatar
15 votes
Accepted

Conformal mappings that preserve angles and areas but not perimeters?

No. Either condition implies $|\,f'(z)| = 1$ for all $z$ in the domain of $\,f$, which in turn implies that $\,f'(z)$ is locally constant (for instance using the open mapping theorem) and thus that $ …
Noam D. Elkies's user avatar
2 votes

Zeroes of trigonometric-like function

Robert Israel's calculations suggest that if $0<a<b$ then $f(z)$ has infinitely many zeros near but not on the imaginary axis, at least on certain rational rays $b=ra$ such as Robert's example with $ …
Noam D. Elkies's user avatar
3 votes

What is $\sum (x+\mathbb{Z})^{-2}$?

For the record, one can prove the product formula for the sine without complex analysis (and without the Gamma function), from which (as David Speyer noted) one can recover $\sum_{i \in \bf Z} (x+i)^{ …
Community's user avatar
  • 1
65 votes

Absolute value inequality for complex numbers

In general, once you've proven an inequality like this in ${\bf R}$ it holds automatically in any Euclidean space (including ${\bf C}$) by averaging over projections. ("Inequality like this" = inequa …
Noam D. Elkies's user avatar
11 votes
Accepted

Abscissa of convergence of Dirichlet series

That's not true even for power series with real coefficients. Let $$ D(s) = \sqrt{1-2^{-s}} = 1 - \frac12 2^{-s} - \frac18 4^{-s} - \frac1{16} 8^{-s} - \frac5{128} 16^{-s} - \cdots . $$ Then $P(s) = …
Noam D. Elkies's user avatar
4 votes

construct a power series with infinitely many zeros in the complex plane, bounded coefficien...

It's been noted already in the comments that the problem is still too easy as stated, because one can easily find functions $f(z) = \sum_{n=0}^\infty c_n z^n$ such as $f(z) = \sin(1 / (r-z))$, with in …
Noam D. Elkies's user avatar
4 votes

on completeness of R_mn, the set of all rational functions of type (m,n)

At the risk that I'm doing somebody's homework... Yes, $R_{m,n}[a,b]$ is complete with respect to the uniform metric $\left\| \cdot \right\|$. Let $f \in {\cal C}([a,b])$ be a uniform limit of ratio …
Noam D. Elkies's user avatar
1 vote

The integral inequality

No, such an inequality need not hold: one can construct $f$ of exponential type and a sequence $\{a_n\}$ of real numbers such that $$ \frac1{f(a_n)} \int_{a_n - \frac12}^{a_n - \frac12} \left|\phant …
Noam D. Elkies's user avatar
1 vote

Complex Zeroes of Stirling functions of the second kind

Alexandre Eremenko already showed that for each $n>1$ the function $$ S_n(x) := \frac1{n!} \sum_{k=1}^n {n \choose k} (-1)^{n-k} k^x $$ has infinitely many zeros $x \in {\bf C}$. One can still say mor …
Noam D. Elkies's user avatar
24 votes

Rational functions with a common iterate

Over ${\bf C}$, An easy counterexample to question 3 is $f(x) = x^2$, $g(x) = cx^2$ where $c$ is a nontrivial cube root of unity. Then $f(f(x)) = g(g(x)) = x^4$ but $f$ and $g$ do not commute. There a …
Noam D. Elkies's user avatar

15 30 50 per page