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Complex analysis, holomorphic functions, automorphic group actions and forms, pseudoconvexity, complex geometry, analytic spaces, analytic sheaves.
1
vote
The integral inequality
No, such an inequality need not hold: one can construct $f$ of
exponential type and a sequence $\{a_n\}$ of real numbers such that
$$
\frac1{f(a_n)} \int_{a_n - \frac12}^{a_n - \frac12}
\left|\phant …
21
votes
Integral of $\log|e^{it}-1|$
Here's another elementary proof, again assuming one has checked that
the integral converges absolutely despite the singularity at $t=0$.
Let $I$ be the average of the $2\pi$-periodic function
$\log \l …
3
votes
What is $\sum (x+\mathbb{Z})^{-2}$?
For the record, one can prove the product formula for the sine without complex analysis (and without the Gamma function), from which (as David Speyer noted) one can recover $\sum_{i \in \bf Z} (x+i)^{ …
4
votes
on completeness of R_mn, the set of all rational functions of type (m,n)
At the risk that I'm doing somebody's homework...
Yes, $R_{m,n}[a,b]$ is complete with respect to the uniform metric
$\left\| \cdot \right\|$.
Let $f \in {\cal C}([a,b])$ be a uniform limit of ratio …
11
votes
Accepted
Abscissa of convergence of Dirichlet series
That's not true even for power series with real coefficients.
Let
$$
D(s) = \sqrt{1-2^{-s}}
= 1 - \frac12 2^{-s} - \frac18 4^{-s} - \frac1{16} 8^{-s} - \frac5{128} 16^{-s}
- \cdots .
$$
Then $P(s) = …
1
vote
Complex Zeroes of Stirling functions of the second kind
Alexandre Eremenko already showed that for each $n>1$ the function
$$
S_n(x) := \frac1{n!} \sum_{k=1}^n {n \choose k} (-1)^{n-k} k^x
$$
has infinitely many zeros $x \in {\bf C}$.
One can still say mor …
4
votes
Accepted
Sums of entire surjective functions
One expects there to be no such $a_n$ in general, because the
"typical" entire functions is surjective (those that aren't are of the
special form $z \mapsto c + \exp g(z)$). An explicit example is
$ …
4
votes
Accepted
A generalization of polynomial algebra on a Riemann surface
Counterexample to the first question ("is $A$ an algebra of functions?"):
Let $M$ be a vertical strip such as {$x + iy : 0 < x < 1$},
and define $f_1,f_2$ as the restriction to $M$ of the
entire func …
65
votes
Absolute value inequality for complex numbers
In general, once you've proven an inequality like this in ${\bf R}$
it holds automatically in any Euclidean space (including ${\bf C}$)
by averaging over projections. ("Inequality like this" = inequa …
9
votes
Question on a Basel-like sum
[Edited to fill in a couple of steps, correct some typos,
standardize the $L$-function notation,
and add comments about the relation with the "Basel sum"]
Here's a proof via transformation of the sum …
8
votes
Accepted
Modular form not meromorphic at $\infty$
[expanding on my comment to convert it to an answer]
An example is $e^j \varphi$ where $j$
is the $j$-invariant and $\varphi$ is any nonzero form of weight $k$.
In general a holomorphic (or meromorphi …
16
votes
Accepted
A statement on complex polynomials
The conjecture is easily seen to be true for $n<3$.
We give a counterexample for $n=3$.
Let $p_i = z^2 - \omega_i$ where the $\omega_i$ are the cube roots of unity.
These are linearly dependent becaus …
32
votes
Accepted
A 14th and 26th-power Dedekind eta function identity?
This question asks in effect to show that $\eta^n$ is a $\pm p^{n/2}$
eigenfunction for the Hecke operator $T_p$. The claim holds because
each of these $\eta^n$ happens to be a CM form of weight $n/2 …
24
votes
Rational functions with a common iterate
Over ${\bf C}$, An easy counterexample to question 3 is
$f(x) = x^2$, $g(x) = cx^2$ where $c$ is a nontrivial cube root of unity.
Then $f(f(x)) = g(g(x)) = x^4$ but $f$ and $g$ do not commute.
There a …
15
votes
Accepted
Conformal mappings that preserve angles and areas but not perimeters?
No.
Either condition implies $|\,f'(z)| = 1$ for all $z$ in the domain of $\,f$,
which in turn implies that $\,f'(z)$ is locally constant
(for instance using the open mapping theorem) and thus that
$ …