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Topological quantum field theory.
8
votes
1
answer
249
views
Is Yetter's invariant multiplicative under connected sum?
Classical formulation
Consider the (untwisted) Dijkgraaf-Witten invariant, defined for an oriented, connected, closed manifold $M$ and a finite group $G$:
$$DW_G(M) := \lvert \operatorname{Hom}(\pi_ …
8
votes
1
answer
350
views
Does the notion of a "coherent state" exist in TQFTs? (ETQFTs?)
In the quantum harmonic oscillator, there exists a family of states called coherent states which form an overcomplete set of states. They are regarded as "the states most resembling classical states", …
10
votes
1
answer
274
views
Are there 4d state sum models, extended TQFTs or chain mail invariant that detect smooth str...
A state sum model is a smooth invariant defined on smooth triangulated, or PL manifolds, by summing a local partition function over labels attached to the elements of the triangulation.
Typical exampl …
10
votes
1
answer
449
views
Which manifolds are sensitive to the cocycle in the Dijkgraaf-Witten model?
Often, TQFTs are defined in families, parametrised by some algebraic data. For example, the Turaev-Viro-Barrett-Westbury TQFTs are parametrised by spherical fusion categories, the Crane-Yetter TQFTs a …
17
votes
2
answers
1k
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How are the Walker-Wang TQFT and the Crane-Yetter TQFT related?
Mathematical physicists in solid state physics and topological insulators talk a lot about Walker-Wang models, which are a family of Hamiltonians defined on a 3d lattice. Unfortunately, the original p …
7
votes
0
answers
453
views
Is there a higher, "orientalish" version of geometric realisation?
Geometric realisation of simplicial sets can be roughly thought of like this:
In some category $\mathcal{C}$, we choose an object for every abstract $n$-simplex. In topological spaces, we would choo …
8
votes
0
answers
370
views
Is there a classification of 2d extended TQFTs with defects?
Chris Schommer-Pries has classified 2d extended TQFTs (topological quantum field theories) in his PhD thesis. The result is a (not necessarily abelian) separable symmetric Frobenius algebra (possibly …
9
votes
1
answer
639
views
Is Turaev-Viro-Barrett-Westbury stronger than homotopy?
I've heard that Reshetikhin-Turaev (RT) is stronger than homotopy, and it can distinguish certain homotopy-equivalent, but non-homeomorphic Lens spaces (I think $L(7,1)$ and $L(7,2)$). Now the Turaev- …
8
votes
1
answer
184
views
Can I recover a crossed module by its homomorphisms?
This is a follow up to this question.
Imagine there is a finitely presented crossed module $\mathcal{G} = (G,H, -\triangleright-\colon G \to \operatorname{Aut}(H), \delta\colon H \to G)$ which I do …
14
votes
1
answer
647
views
Is there a PL, or topological, bordism hypothesis?
The bordism hypothesis says that the $(\infty, n)$-category of smooth, framed $n$-bordisms, $(n-1)$-dimensional boundaries, and corners down to points, is freely generated symmetric monoidal with dual …
14
votes
2
answers
729
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Is a unitary Hamiltonian TQFT the same as a unitary axiomatic TQFT?
Introduction
Axiomatic TQFTs
An axiomatic $n$-dimensional TQFT is a symmetric monoidal functor $\mathcal{Z}\colon \operatorname{Bord}_n \to \operatorname{Hilb}$ from $n$-dimensional oriented bordism …
10
votes
2
answers
598
views
What are TQFTs that are multiplicative under connected sums? Do bordisms with connected sum ...
In general, one extracts a manifold invariant from a TQFT by interpreting the closed manifold as a bordism from the empty set to the empty set. The TQFT sends this bordism to a homomorphism of the gro …
6
votes
1
answer
337
views
Is there a quotient or exact sequence of symmetric, premodular (ribbon fusion) and modular c...
In Walker and Wang's article about (3+1)-TQFTs from premodular categories, they say on page 14 that you can take a quotient of a premodular category $\mathcal{C}$ by its symmetric fusion subcategory …