Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
0
votes
Rectifiable currents
A rectifiable curve (in the sense of, for example, baby Rudin, p. 136) in Euclidean space or a metric space more generally, is precisely a continuous curve with finite length.
1
vote
Extending connections
Question 1: Domain and target; the $\nabla$ takes $\Omega(M,E)$ to itself.
Question 2: Property (*) defines the extension on pure wedge products $\omega \wedge \sigma$, but every element of $\Omega(M …
6
votes
Connections with the same geodesics
You are looking for the theory of projective connections. See the paper of Molzon and Mortensen, The Schwarzian derivative for maps between
manifolds with complex projective connections, Trans. Amer. …
0
votes
Lorentzian metrics on a disk up to conformal equivalence
Here is the main idea. Suppose that the metric extends smoothly to the boundary. Such a metric has two null directions at each point. Follow one until you reach the boundary, and then switch to the ot …
1
vote
parallelism of vector bundles
If we take a basis $\sigma_A$ of local sections of $E$, any connection on $E$ is expressed as $\nabla \sigma_A = \gamma^B_A \sigma_B$, where $\gamma^B_A$ are the connection 1-forms. On $E^*$, the indu …
2
votes
pullback of Lie algebra cocycles along Cartan connections
I am fairly certain that no one has considered pullbacks of Lie algebra cocycles in the context of Cartan geometries.
1
vote
extension of frame fields on surfaces
It is not always possible, for example you cannot extend the unit normal vector to the 2-sphere to a nonzero vector field inside the ball. I gave this problem on my 3rd year undergraduate analysis exa …
4
votes
When does Laplace operator commute with isometries?
Always: the definition of $\Delta_g$ is in terms of $g$, so any diffeomorphism preserving $g$ preserves $\Delta_g$, and this is what ``preserves'' means.
2
votes
Connection on a restricted bundle
If $H$ is a reductive group (for example, compact or semisimple), then the representation $\mathfrak{g}$ splits over $H$, and you do indeed get an induced connection, by splitting $\omega$ into its pa …
16
votes
Accepted
Given Gaussian curvature, can one construct a metric to fulfill the Gauss-Bonnet theorem?
If $K$ is to be the Gauss curvature of some metric on a compact two-dimensional manifold $M$ with Euler characteristic $χ(M)$, then from the Gauss-Bonnet theorem one has the following conditions: (a) …
2
votes
smooth connection on exterior power
If two vector bundles $V_1$ and $V_2$ have connections $\nabla_1$ and $\nabla_2$, then the vector bundle $V=V_1 \otimes V_2$ has a unique connection $\nabla$ for which $\nabla(s \otimes t)=(\nabla_1 s …
1
vote
Notation for high order partial covariant derivative
There is no standard notation. The problem is simply the noncommutativity, making the expressions unwieldy. It is rare in geometry to differentiate many times using a connection. Twice is usually enou …
5
votes
Accepted
Invariants for subspaces of product manifolds
There is a theory due to Tresse, which is unfortunately fairly complicated. It is explained, at least partly, in the book of Arnol'd, Geometric Methods in the Theory of Ordinary Differential Equations …
1
vote
Isometric embedding of the modular surface
Correction: The following idea doesn't work as stated, because (as Robert points out) the cusp and cones allow points where mean curvature is not defined.
If you could isometrically and smoothly embed …
2
votes
Signed nD curvature
I think you are probably looking to find an analogue of the Serret--Frenet theory for higher dimensional submanifolds of Euclidean space; this is discussed in detail in What is the analog of the "Fund …