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In algebraic geometry, a projective variety over an algebraically closed field $k$ is a subset of some projective $n$-space $\mathbb P^n$ over $k$ that is the zero-locus of some finite family of homogeneous polynomials of $n + 1$ variables with coefficients in $k$, that generate a prime ideal, the defining ideal of the variety

2 votes
2 answers
289 views

Does a smooth cubic in $P^3$ have projectively isomorphic sections?

We will be working over an algebraically closed field of characteristic 0. We say that a projective variety $X\subset \mathbb{P}^n$ has projectively isomorphic plane sections if there is an open set $ …
Sergey Guminov's user avatar
5 votes
0 answers
188 views

Description of determinantal varieties in $\mathbb{P}^n$ that are linear sections of determi...

Fix an algebraically closed field $k$ of characteristic 0. Consider an $n$-tuple $(A_1,\ldots, A_n)$ of $n\times n$ matrices over $k$ and assign to it the determinantal surface in $\mathbb{P}_k^{n-1}$ …
Sergey Guminov's user avatar
3 votes
0 answers
325 views

Learning about determinantal varieties

In my research I recently stumbled upon a problem which involves trying to identify whether a given projective variety is determinantal or, even stronger, determinantal of a particular form. For exam …
Sergey Guminov's user avatar