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The Riemann zeta function is the function of one complex variable $s$ defined by the series $\zeta(s) = \sum_{n \geq 1} \frac{1}{n^s}$ when $\operatorname{Re}(s)>1$. It admits a meromorphic continuation to $\mathbb{C}$ with only a simple pole at $1$. This function satisfies a functional equation relating the values at $s$ and $1-s$. This is the most simple example of an $L$-function and a central object of number theory.

8 votes
2 answers
757 views

Are there known non-real zeros of derivatives of Riemann zeta with 0 < Re(s) < 1/2?

According to New zero free regions for the derivatives of the Riemann zeta function assuming the Riemann Hypothesis, $\zeta^{(k)}(s)$ has at most a finite number of non-real zeros with $\operatorname{ …
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3 votes
1 answer
414 views

How is "large" defined in an equality for the modulus of Riemann zeta?

This paper p.4 claims: Corollary C. Assume RH. For all large $t$ we have $$|\zeta(\frac12 +it)| \le \exp\left(\frac38 \frac{\log{t}}{\log{\log{t}}}\right) \qquad (1) $$ $t$ a Gram points often appe …
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4 votes
0 answers
185 views

Nearest integers to derivatives of zeta

Closely related, but different from this solved quesion Let $\zeta^{(k)}(s)$ denote the $k$-th derivative of Riemann zeta function. For real $x$, let $[x]$ denote the nearest integer to $x$. Conjectur …
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2 votes
2 answers
547 views

What are the fallacies that this RH inequality may fail at most finitely often?

According to "EQUIVALENCES TO THE RIEMANN HYPOTHESIS p.4 Let $g(n)$ be the maximal order of a permutation of n objects RH Equivalence 3.3. The Riemann Hypothesis is equivalent to $\log{g(n)} < Li^{ …
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19 votes
4 answers
3k views

zeta(3) in terms of derivatives of zeta at 1/2 and pi

Got numerical support that for odd $n$, $\zeta(n)$ might be expressed in terms of the derivatives of $\zeta(\frac12)$. Based on More Zeta Functions for the Riemann Zeros, Andre Voros, p.12, Table 3: …
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7 votes
0 answers
421 views

$\zeta(x)$ in terms of $\zeta'(x),\zeta'(1-x),\Gamma,\psi$

By differentiating $\xi$ and solving for $\zeta(1-x)$: $$ \zeta(1-x) = \frac{2(\zeta'(x)\Gamma(x/2)+\Gamma((1-x)/2) \zeta'(1-x)\pi^{x-1/2}) )}{\Gamma((1-x)/2) \pi^{-1/2+x}(2\log\pi -\psi((1-x)/2)-\p …
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8 votes
1 answer
623 views

Is there always a zero between consecutive local extrema of $\Re \zeta(1/2+it)$ (or $\Im \ze...

Based on limited numerical evidence, I am inclined to suspect that there is always zero of $\Re \zeta(1/2+it)$ between consecutive local extrema of $\Re \zeta(1/2+it)$ (and the same for $\Im \zeta(1/2 …
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3 votes
2 answers
464 views

On the critical line $ \Re \zeta'(s)/\zeta(s) =? 1/2 \log(\pi) - 1/2 \Re \psi(s/2)$ ?

For $\Re s = 1/2$ numerical evidence suggest: $$ \Re \zeta'(s)/\zeta(s) = 1/2 \log(\pi) - 1/2 \Re \psi(s/2) \qquad (1) $$ How this was found. Consider the symmetrized zeta function $\zeta^*(x)= \pi^{- …
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6 votes
2 answers
691 views

Bounds for $\sum_{k=1}^\infty\frac{(-1)^{k+1}x^k}{(k-1)!\zeta(2k)}$

Let $$ f(x) = \sum_{k=1}^\infty\frac{(-1)^{k+1}x^k}{(k-1)!\zeta(2k)}$$ Are there lower bounds, upper bounds or (unlikely) simpler closed form for $f(x)$? The bounds for Bernoulli numbers I fou …
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4 votes
1 answer
1k views

zeta(2k+1) is a rational multiple of pi^{2k} zeta'(-2 k) ?

Probably this is well know and elementary and will delete it, but couldn't find it on the web. Got a sketch of proof and numerical evidence that $\zeta(2k+1)$ is a rational multiple of $\pi^{2k} \ze …
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2 votes
0 answers
363 views

Complex zeros of $\zeta'(s)/\zeta(s) + \zeta'(1-s)/\zeta(1-s) $ = simpler expression (except...

Let $ G(s) := \frac{\zeta'(s)}{\zeta(s)} + \frac{\zeta'(1-s)}{\zeta(1-s)}$ where $s$ is not a zero of zeta. $G$ has real zeros and a pair of complex zeros near $\frac12 \pm 6i$. Partial results: By …
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3 votes
2 answers
495 views

Finite sum seemingly related to nontrivial zeta zeros

For $t \in \mathbb{R}$ define $$ F(t) = \sum_{n=1}^{[t]} \frac{(-1)^{(n-1)}}{n^{\frac12 + it}}$$ Let $\operatorname{Arg}(t)$ be $\operatorname{atan2}(\Im t , \Re t)$ - basically this is $\arctan$, but …
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1 vote
0 answers
132 views

Conjectured alternate form for vanishing of $\Re\zeta(1/2+it)$ except at zeros

Heavily based on Agno's question. Define: $$ \chi(s)=\pi^{-(\frac{s}{2})} \Gamma(\frac{s}{2}) $$ Agno conjectured: only for $\sigma=\frac12$, $\Re(\chi(s)) = \Re(\zeta(s)) =0$ is always true, except …
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7 votes
0 answers
156 views

How comes vanishing of the real part of function involving zeta is very well approximated by...

In this question Agno asked about the zeros of $\zeta\left(\frac{s}{a}\right) \pm \zeta\left(\frac{1-s}{a}\right)$. I fixed $a=2$ and the minus sign and defined: $$ f(s)=\Re \left( \zeta\left(\frac{ …
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4 votes
1 answer
464 views

Is this differential equation for zeta on the critical line? One can compute it from its der...

Looks like on the critical line one can compute $\zeta(1/2+it)$ from $\zeta^{'}(1/2+it)$ and simpler functions. Let $$ \begin{aligned} f(t)= & 2\, \left( {\frac { \left( \left| \zeta^{'} \left( 1/ …
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