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Questions about the branch of combinatorics called graph theory (not to be used for questions concerning the graph of a function). This tag can be further specialized via using it in combination with more specialized tags such as extremal-graph-theory, spectral-graph-theory, algebraic-graph-theory, topological-graph-theory, random-graphs, graph-colorings and several others.

2 votes
0 answers
68 views

Is this infinite family of non-trivial snarks resulting from the first Celmins-Swart?

Non-trivial snark is cubic graph with chromatic index $4$, girth at least $5$ and doesn't to contain three edges whose deletion results in a disconnected graph, each of whose components is nontrivial. …
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3 votes
1 answer
103 views

Let $S$ be the nonempty set of strongly regular graphs with given parameters. Must $S$ conta...

As the title says, let $S$ be the nonempty set of strongly regular graphs with given parameters. Must $S$ contain vertex transitive graph? I suspect the most likely counterexample would be $|S|=1$.
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7 votes

Independence Number of Graphs

This is false. Let $G$ be with edges $ [(0, 2), (0, 3), (0, 5), (1, 3), (1, 4), (1, 5), (2, 4), (2, 5), (3, 5), (4, 5)] $ and $H$ with edges $[(0, 2), (0, 3), (0, 4), (0, 5), (1, 2), (1, 3), (1, 4) …
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1 vote

What is the independence number of hamming graph?

Experiments suggest it might be $q^{d-1}$. Here is data from sage: d= 2 q= 2 alpha= 2 factor= 2 alpha - q^(d-1) 0 d= 2 q= 3 alpha= 3 factor= 3 alpha - q^(d-1) 0 d= 2 q= 4 alpha= 4 factor= 2^2 alp …
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4 votes
Accepted

Genus of a simple graph

Second try. I believe $K_{6,3}$ is a counterexample. It is genus $1$ and contains $2$ edge disjoint $K_{3,3}$s sharing only $3$ vertices. Explicitly: K_{6,3}=[(0, 6), (0, 7), (0, 8), (1, 6), (1, 7) …
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2 votes
0 answers
124 views

Maximizing the minimum outdegree of digraph without $m$ cycle

Let $G$ be a simple digraph on $n$ vertices without a directed cycle of length $m$ (it may have directed cycles of length less than $m$. The cycles need not be simple). How large the minimum outde …
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7 votes
Accepted

A conjecture about Hamiltonian cycle

I think Gordon Royle and Joseph O'Rourke answer it here A graph is uniquely hamiltonian if it has exactly one Hamilton cycle Apparently, however, there are uniquely hamiltonian graphs with minimum de …
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2 votes

Is there any partition of a regular graph which in any part there exists a vertex with all i...

I think this is possible. First note that it if the graph is disconnected it is trivial. Consider two copies of this graph: Vertices $4$ and $5$ are degree $3$ and all other are $4$. Vertex $3$ …
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1 vote
0 answers
47 views

Complexity of computing the Tutte polynomial of multigraph when the Tutte polynomial of the ...

Let $G$ be multigraph with $l$ loops and $m$ multiple edges and $G'$ be the underlying simple graph (loops and multiple edges removed). Assume the Tutte polynomial of $G'$ is given. Q1 What is th …
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5 votes
1 answer
218 views

Complexity of counting MAXCUT in planar graphs -- seemingly contradicting claims

Confusion is likely. Appears to me two papers give contradicting claims about the complexity of counting MAXCUT in planar graphs. Exact Max 2-SAT: Easier and Faster p. 6 However, counting the num …
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0 votes
0 answers
154 views

For which matrices deciding permutation similarity is polynomial?

Q1 For which matrices deciding permutation similarity is polynomial? It is not easier than graph isomorphism (and very likely is equivalent to it). If necessary, assume the entries are nonnegati …
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2 votes
1 answer
180 views

Graph classes where finding explicit coloring have certificate that it is minumum

Graph coloring doesn't have certificate that smaller coloring doesn't exist in general. I am looking for graph classes where finding explicit coloring is not polynomial and have polynomially verifiab …
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5 votes
Accepted

Number of graphs on a given set of vertices with maximum degree of $2$

This is OEIS A003292 Number of 4-line partitions of n decreasing across rows. a(n) is the number of unlabeled graphs on n nodes whose connected components are a path or a cycle. - Geoffrey Critzer …
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3 votes
Accepted

Can the Vertices of cubic graph be partitioned into and induced cycle and a forest?

I believe this is false. EDIT The previous counterexample was wrong, let me try again. A program found counterexample on $10$ vertices and exhaustive search confirmed it. The edges are: [(0, 3), …
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2 votes
1 answer
259 views

The edge chromatic number and pefectness of inflation of cubic graph

The inflation of graph $G$ is a graph $I(G)$ which is obtained by replacing each vertex $x$ by a complete graph $K_{\deg(x)}$ and joining each edge to a different vertex of $K_{\deg(x)}$. Let $G$ b …
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