Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
4
votes
1
answer
199
views
Do (co)density (co)monadic constructions stablize?
It does not say explicitly, but by considering left/right Kan extension/lift, it could make sense to talk about four variants: (co)density (co)monads. … And since $TF$ is a functor, we can construct its (co)density (co)monads iteratively.
Question
Does such iterative construction stablize?
If not, what's the state of the art about it? …
7
votes
2
answers
545
views
A specific property of bi-adjunction
The corresponding (co)monads are Frobenius monads. I've looked in some paper about them, and couldn't find this structure discussed. …
6
votes
0
answers
350
views
Cohomology without comonad?
TL;DR. Many cohomologies can be unified using comonads. Question: which cohomologies cannot be?
For each algebraic theory, there is an adjunction, and therefore a (co)monad (or called a (co)triple). …