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Real-valued functions of real variable, analytic properties of functions and sequences, limits, continuity, smoothness of these.

6 votes

"Simple" integral equation

Alternative simple proof - integration by parts: $$ \int_0^{1-a}\frac{H(z)}{1-z}dz=\int_0^{1-a}\frac1{(1-z)^2}\int_z^1\frac{2\zeta}{1+\zeta}H(\zeta^2)d\zeta= $$ $$ \frac1{1-z}\int_z^1\frac{2\zeta}{1 …
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11 votes
3 answers
1k views

"Simple" integral equation

Let $H(z)$ be a continuous solution of the problem $$ H(z)=\frac1{1-z}\int_z^1 \frac{2\zeta}{1+\zeta} H(\zeta^2)\,d\zeta,\ \ \ z\in[0,1);\ \ \ H(1)=1. $$ Is it true that $H(0)=1-\ln2$? The question i …
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