Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with differential-equations
Search options not deleted
user 121820
Ordinary or partial differential equations. Delay differential equations, neutral equations, integro-differential equations. Well-posedness, asymptotic behavior, and related questions.
3
votes
The linearization problem of fully nonlinear equation on standard sphere
Here is my favorite way to do this computation.
Let
$$ \delta_{i_1 \dotsm i_k}^{j_1 \dotsm j_k} = \begin{cases} \mathrm{sgn}\, \sigma, & \text{if $j_k = i_{\sigma(k)}$}, \\ 0, & \text{otherwise} \end{ …
- 1,713
7
votes
Nirenberg problem in conformal change
Yes, it is true. This is a consequence of the conformal invariance of the conformal Laplacian.
Let $(M^n,g)$ be a Riemannian manifold. The conformal Laplacian is
$$ L_2^g = -\Delta + \frac{n-2}{4(n- …
- 1,713
2
votes
Kelvin transformation in fully nonlinear equation
This follows easily from the fact that the Kelvin transform is a conformal diffeomorphism and the naturality of the Schouten tensor.
Let $\Phi(z) := \frac{z}{\lvert z\rvert^2}$ denote the Kelvin trans …
- 1,713