Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 121595

In algebraic geometry, a projective variety over an algebraically closed field $k$ is a subset of some projective $n$-space $\mathbb P^n$ over $k$ that is the zero-locus of some finite family of homogeneous polynomials of $n + 1$ variables with coefficients in $k$, that generate a prime ideal, the defining ideal of the variety

5 votes

How many holes may a projection of an algebraic variety have?

Blow up to get a morphism $\Pi: Bl_{P_0}\mathbf P^n \rightarrow \mathbf P^{n-1}$. Let $\widetilde{V}$ be the proper transform of $V$ in $Bl_{P_0}\mathbf P^n$. Then $\overline{\pi(V)}=\Pi(\widetilde{V} …
Pop's user avatar
  • 887
3 votes

Degree of a variety vs degree of its blow-up

First, the ample divisors on $\mathbf P^n \times \mathbf P^{n-1}$ are of the form $aH_1+bH_2$ for $a,b>0$, which means that every ample divisor is of the form $H_1+H_2+N$ for some nef divisor $N$. Thi …
Pop's user avatar
  • 887
6 votes

existence of birational morphism and divisors

I don't know where to find a proof written, but it is not hard to give one here. One direction is easy. If $S \rightarrow \mathbf P^2$ is a birational morphism, then let $D$ be the pullback of a hyper …
Pop's user avatar
  • 887